Proving Subgroup Equality in Group Theory

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To prove that Ha = H if and only if a belongs to H, one must understand that Ha represents the set of all products of elements from H with the element a. If Ha equals H, it implies that every element in H can be expressed as h*a for some h in H, indicating that a must also be in H. For the second part, to show H² = H, it is necessary to demonstrate both H² ⊆ H and H ⊆ H², leveraging the properties of subgroups, particularly closure under multiplication. The closure property ensures that multiplying elements of H will yield elements that remain within H, confirming the equality. Understanding these relationships is crucial for proving subgroup equality in group theory.
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Homework Statement



let H a subgroup of G. Prove that:
1) Ha=H iff a belong to H
2) H2=H

Homework Equations





The Attempt at a Solution

 
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ranoo said:

Homework Statement



let H a subgroup of G. Prove that:
1) Ha=H iff a belong to H
2) H2=H
What does Ha mean? What does it mean to multiply a subgroup by itself?
 
I don't know, like this we took in the homework.
 
Ha is the set containing all elements of the form h*a, where h is in H.

What is the definition of a subgroup? It must non-empty, closed under multiplication and closed under inversion. So if Ha = H, then h_{1}a = h_{2}. What does this say about a?

If a is in H on the other hand, and H is closed under multiplication, what does this say about Ha?

Finally, to prove that H^2=H, we need to show that H^{2} \subseteq H and H \subseteq H^{2}. First, naively, which one is definitely contained in which? Next, if H is closed under multiplication, what does this say about the relation between H and H^2?

Good luck!
 
thank you very much
 
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