Proving that T=T* for a Normal Linear Transformation

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SUMMARY

The discussion centers on proving that a normal linear transformation \( T \) satisfies \( T = T^* \) given the condition \( T^2 = \frac{1}{2} (T + T^*) \). The approach involves analyzing the matrix representation \( \mathbf{A} = [T]_B \) in an orthonormal basis \( B \) and demonstrating that all eigenvalues \( \lambda \) are real. The proof leverages the theorem stating that if the characteristic polynomial of a normal transformation can be factored into linear factors over \( \mathbb{R} \), then \( T \) is Hermitian, leading to the conclusion that \( T = T^* \).

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  • Understanding of linear transformations and their properties
  • Familiarity with Hermitian matrices and eigenvalues
  • Knowledge of normal operators in linear algebra
  • Concept of characteristic polynomials and their factorization
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  • Study the properties of normal linear transformations in detail
  • Learn about Hermitian matrices and their implications in linear algebra
  • Explore the proof techniques for eigenvalue problems in linear transformations
  • Investigate the relationship between characteristic polynomials and matrix diagonalization
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Students and researchers in mathematics, particularly those focused on linear algebra, eigenvalue problems, and the properties of linear transformations.

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Homework Statement


let T:V \to V be a linear transformation which satisfies T^2 = \frac{1}{2} (T + T^*) and is normal. Prove that T=T^*.


Homework Equations





The Attempt at a Solution


I think we should start like this:
Let \mathbf{A}=[T]_B be the matrix representation of T in the orthonormal base B. We look at A as a matrix in the Complex plane. If we prove that for every Eigenvalue, \lambda, it happens that \lambda \in \mathbb{R}, then T = T^* by a theorem and we finished.
Now, be \mathbf{x} an Eigenvector that satisfies \mathbf{Ax} = \lambda \mathbf{x}, then <\mathbf{Ax},\mathbf{x}> = \lambda ||\mathbf{x}||^2 and \lambda = \frac{<\mathbf{Ax},\mathbf{x}>}{||\mathbf{x}||^2}. If only I could show that <\mathbf{Ax},\mathbf{x}> is a real number, I solved it.
 
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Prove that the transformation is hermitian, once you do it's pretty east to prove that eigenvalues of a hermitian transformation are real.
 
It doesn't help me, because I plan to show that the transformation is Hermitian by the following theorem:
"If T is a normal transformation whose Characteristic polynomial can be completely factored into linear factors over \mathbb{R}, then T is Hermitian".
And then it follows, of course, that T = T*
 
Can someone help me please? I work on it two days. Nothing works. Please. I spent hours.
 

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