Proving the Multiplication of Even Integers is a Multiple of 4: A Simple Proof

AI Thread Summary
The discussion focuses on proving that the product of any two even integers is a multiple of 4 using direct proof. The definition of even integers is established as n=2k and n=2j for integers k and j. The proof demonstrates that multiplying two even integers, represented as 2k and 2j, results in 4kj, confirming it is a multiple of 4. A suggestion is made to use different letters for the two integers to avoid confusion. The proof is correctly set up and leads to the conclusion that the product is indeed a multiple of 4.
nastygoalie89
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Homework Statement



Use direct proof to prove "The product of any two even integers is a multiple of 4."

Homework Equations



definition of even is n=2k

The Attempt at a Solution



My proof is going in circles/getting nowhere.

So far I have (shortened): By definition even n=2k, n=2j for some integer k
2k(2j) = 4kj = 4(kj) kj is an integer because k and j are integers
and the product of two integers is an integer
Not sure where to take it from there or if I even set the proof up correctly!
 
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nastygoalie89 said:

Homework Statement



Use direct proof to prove "The product of any two even integers is a multiple of 4."

Homework Equations



definition of even is n=2k

The Attempt at a Solution



My proof is going in circles/getting nowhere.

So far I have (shortened): By definition even n=2k, n=2j for some integer k
2k(2j) = 4kj = 4(kj) kj is an integer because k and j are integers
and the product of two integers is an integer
Not sure where to take it from there or if I even set the proof up correctly!
You have the gist of it, but you should use different letters for the two even integers, say m and n.

m = 2k, and n = 2j, for integers k an j
mk = (2k)(2j) = 4kj, which is obviously a multiple of 4.
 
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