 #1
 2
 0
Homework Statement
M1 has a mass of 6.51 kg. It is on a horizontal surface, connected by a light string to a hook. Mass M2 can be increased smoothly by adding masses little at a time. The pulley has a negligible mass and no friction.
When M2 is 3.12 kg it begins to accelerate downwards at a rate of 1.52 m/s2. Calculate mu static mu kinetic for M1 on the surface.
I was also given this hint, First calculate ms (from knowing the force it takes to begin moving) and then mk (from the given acceleration) and subtract
Homework Equations
F= Ma
Mass2
Fnety = TMg
Mass1
Fnetx= TFstatic
Fs= Mus*Fn
Fk= Muk* FN
The Attempt at a Solution
Mass2
Fnety = TMg
4.74N= T30.576N
T= 25.83
Mass1
Fnetx= TFkinetic
9.89N= 25.8315.934
Fk= Muk*Fn
15.9348/63.798= 25.83
Muk= .24976
Fnet=0
TFs=
25.83
Fs= Mus* FN
25.836= Mus * FN
25.836/63.798
Mus=.405
MusMuk= .155
Attachments

1.9 KB Views: 467