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## Homework Statement

M1 has a mass of 6.51 kg. It is on a horizontal surface, connected by a light string to a hook. Mass M2 can be increased smoothly by adding masses little at a time. The pulley has a negligible mass and no friction.

When M2 is 3.12 kg it begins to accelerate downwards at a rate of 1.52 m/s2. Calculate mu static -mu kinetic for M1 on the surface.

I was also given this hint, First calculate ms (from knowing the force it takes to begin moving) and then mk (from the given acceleration) and subtract

## Homework Equations

F= Ma

Mass2

Fnety = T-Mg

Mass1

Fnetx= T-Fstatic

Fs= Mus*Fn

Fk= Muk* FN

## The Attempt at a Solution

Mass2

Fnety = T-Mg

-4.74N= T-30.576N

T= 25.83

Mass1

Fnetx= T-Fkinetic

9.89N= 25.83-15.934

Fk= Muk*Fn

15.9348/63.798= 25.83

Muk= .24976

Fnet=0

T-Fs=

25.83

Fs= Mus* FN

25.836= Mus * FN

25.836/63.798

Mus=.405

Mus-Muk= .155