Pulley question(Newtons third law)

Click For Summary
SUMMARY

The discussion revolves around calculating the tension in a rope connected to a pulley system involving a 60 kg man and a 100 kg weight. The equations used include T - m1g = m1a and T - m2g = m2a, where T represents tension, m1 is the man's weight, and m2 is the weight on the ground. The key insight provided is that since the man is stationary, the acceleration (a) is 0, simplifying the calculations. This leads to the conclusion that the tension in the rope can be directly calculated using the weight of the man and the gravitational force.

PREREQUISITES
  • Understanding of Newton's laws of motion, particularly Newton's third law.
  • Familiarity with basic physics equations involving tension and gravitational force.
  • Knowledge of how to manipulate algebraic equations to solve for unknowns.
  • Basic understanding of pulley systems and their mechanics.
NEXT STEPS
  • Study the implications of stationary objects in pulley systems and how they affect tension calculations.
  • Learn about the dynamics of multi-body systems in physics, focusing on forces and accelerations.
  • Explore advanced topics in mechanics, such as friction in pulley systems and its effect on tension.
  • Practice solving similar problems involving different weights and configurations of pulleys.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of tension calculations in pulley systems.

Jennifer001
Messages
22
Reaction score
0

Homework Statement



there is a pulley and on one side there's a man hanging on it he weights 60kg on the other side resting on the ground is a 100kg weight. what is the tension on the rope

Homework Equations



T-m1g=m1a
T-m2g=m2a
F=2T-(m1+m2)g

The Attempt at a Solution



T-m1g=m1a T-m2g=m2a
T=m1a+m1g T=m2a+m2g
m1a+m1g=m2a+m2g

then i pulled in the numbers and got
g=a which = 9.8 (gravity)

and now I am stuck.. i think i might have done somethign wrong can someone help?
 
Physics news on Phys.org
Welcome to PF!

Jennifer001 said:
there is a pulley and on one side there's a man hanging on it he weights 60kg on the other side resting on the ground is a 100kg weight. what is the tension on the rope

T-m1g=m1a T-m2g=m2a
T=m1a+m1g T=m2a+m2g
m1a+m1g=m2a+m2g

then i pulled in the numbers and got
g=a which = 9.8 (gravity)

and now I am stuck.. i think i might have done somethign wrong can someone help?

Hi Jennifer001! Welcome to PF! :smile:

Hint: the man is hanging … stationary … so a = 0. :wink:

Try again! :smile:
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K