Q-Factor in Series-Parallel Shunt Circuits

  • Thread starter Thread starter phantomvommand
  • Start date Start date
  • Tags Tags
    Rlc circuit
Click For Summary
SUMMARY

The discussion focuses on the conversion of RL circuits in series to RL circuits in parallel, particularly in the context of resonance. The formula ##\frac {\omega L} {R} = Q## is applicable under specific conditions, particularly when ##R_L >> R##. The conversion is not universally valid, as it only holds true at resonance and for high Q factors, typically above 5. The conversation emphasizes the mathematical similarities between series and parallel circuits while acknowledging the limitations and physical interpretations of these conversions.

PREREQUISITES
  • Understanding of RLC circuit theory
  • Familiarity with resonance concepts
  • Knowledge of impedance and admittance calculations
  • Basic grasp of circuit topology and duality
NEXT STEPS
  • Study the implications of Q factor in RLC circuits
  • Learn about impedance transformation techniques in circuit design
  • Explore the concept of dual circuits and their applications
  • Investigate the mathematical relationships in series and parallel resonance
USEFUL FOR

Electrical engineers, circuit designers, and students studying RLC circuits and resonance phenomena will benefit from this discussion.

phantomvommand
Messages
287
Reaction score
39
Screenshot 2024-11-27 at 11.10.51 PM.png

Screenshot 2024-11-27 at 11.11.11 PM.png


The above content discusses the conversion of RL (in series) to RL (in parallel). Importantly, the context is that the RL (in series) was in parallel with a capacitor.

I am interested to know the following:

Q1. Why is ##\frac {\omega L} {R} = Q## true for this circuit, given that this formula was derived for the pure series RLC circuit (and is not applicable to this RL||C circuit unless we are assuming R-L-C is approximately equal to R-L||C)?

Q2. Notably, the conversion between RL to R||L is not technically true, since it takes ##R_L >> R## and therefore ignores R. Is there a physical interpretation for the technical impossibility of converting from RL to R||L? Related to this, what is the physical meaning of a circuit in a situation where ##R_L## is not much larger than R, and therefore cannot be converted from series to parallel?
 
Last edited:
Engineering news on Phys.org
phantomvommand said:
Notably, the conversion between RL to R||L is not technically true
Yes, It all sounds like BS to me. Although I didn't review it carefully. To say that a series R, L branch can be substituted with parallel R, L equivalent makes no sense to me. Those impedances are only equivalent at a single frequency.

In fact, the dual circuit for a series R, L branch is a parallel G, C loop. But that's a slightly different subject.

My advice: find a better text book; there are many.
 
  • Like
Likes   Reactions: sophiecentaur
DaveE said:
Yes, It all sounds like BS to me. Although I didn't review it carefully. To say that a series R, L branch can be substituted with parallel R, L equivalent makes no sense to me. Those impedances are only equivalent at a single frequency.

In fact, the dual circuit for a series R, L branch is a parallel G, C loop. But that's a slightly different subject.

My advice: find a better text book; there are many.
I should note the text is assuming everything is at resonance. The math seems to work out, but I am interested in understanding the physical significance of being able to perform this switch at resonance for ##R_L >> R##.
 
It is very common when analysing circuits to convert back and forth between series and parallel resistances. An approx method for values of Q above about 5 is to notice that the Q of the component is X/Rs, and also Rp/X. So for a given Q, we can say X/Rs=Rp/X. Actually I think the exact method is to use Q+1 instead of Q.
Converting between series and parallel allows us to add circuit resistances either in parallel or series, as the configuration dictates. It also allows impedance transformation to be obtained, as in the well known L-match circuit.
For a parallel circuit where there is resistance in series with the inductor, it is found for a circuit with low Q that the maximum voltage developed across the circuit and zero phase angle do not quite coincide. I think you would see this by drawing the phasor diagram.
 
  • Like
Likes   Reactions: DaveE
The source impedance, ##R_l##, isn't used anywhere, except in the schematic. So I suppose we can assume it's zero? It, and the source transformation mentioned, seem irrelevant.

Series resonance and parallel resonance are fundamentally different topologies. But, if you restrict your analysis to any single frequency, resonance in this case, you can pretend they are the same. They both have a quadratic term (high Q) somewhere in their factored pole-zero response (impedance, transfer function, etc.).

The canonical form of this term will be ##[1 + (\frac{1}{Q})(\frac{s}{\omega_o}) + (\frac{s}{\omega_o})^2 ]## for ##Q>\frac{1}{2}##
With the associated definitions:
## s = j \omega ## , for steady state or single frequency analysis. s is the Laplace variable used in transient analysis.
## \omega_o = \frac{1}{ \sqrt{LC}} ## , the resonant frequency.
## Zc=\sqrt{\frac{L}{C}} ## , the characteristic impedance.
## Q=\frac{Zc}{R} ## , for series resonance, or ## Q=\frac{R}{Zc} ## , for parallel resonance

Personally, I always found this format easy to remember. It may be worth memorizing.

For example,
The impedance of a series RLC branch is ##Z(s)=sL + R +\frac{1}{sC} = \frac{s^2LC+sRC+1}{sC}##
The admittance of a parallel RLC section is ##Y(s)=sC + \frac{1}{R} +\frac{1}{sL} = \frac{s^2LC+s\frac{L}{R}+1}{sL}##

I doubt that there is any physical significance, it's just that there are useful similarities in the math. There are about a million ways that EEs talk about resonance, if you don't like this approach there are many others on the web. Many are pretty sloppy with underlying assumptions. I prefer to go back to the math, personally.

You may also be interested in exploring the idea of dual circuits. These are different topologically but have the same solutions under a set of duality transformations, which, of course, is applicable here too.
https://www.ams.org/publicoutreach/feature-column/fc-2019-05

PS: Also note that at resonance ##\frac{s}{\omega_o} = j##, which makes the math easy.
 
Last edited:
If you can't ignore one of the resistors, then it is neither a series or parallel resonance and the math is messy:
1732828870052.png
 
Last edited:
I should mention that it is easy to convert an inductor with a physical series resistance to one with a hypothetical parallel resistance, and vice versa. Similarly with a capacitor. The values vary with frequency but there is no requirement for it to be in a resonant circuit. If the component is placed in a black box, at one frequency we cannot tell which form it is.
If you then wish to create a resonant circuit by adding another reactance outside your black box, then use the series values for a series reactance and parallel values for a parallel reactance. Notice that the terms parallel and series refer to the location of the generator, otherwise the two circuits are the same.
Series and parallel conversions:
Let Q = Xs/Rs = Rp/Xp
Xs = Q x Rs
Xp=Rp/Q
Rs=Rp/(Q^2+1)
Rp=Rs(Q^2+1)
And as I mentioned previously, where Q is greater than about 5 it is possible for most engineering purposes to use Q^2 instead of Q^2+1.
Where you have a messy circuit, such as parallel LC with parallel R but also having resistor in series with the combination, then convert the LCR resonant circuit to series values and then place the external resistor in series with it by simple addition of the two resistances.
 
  • Like
Likes   Reactions: DaveE

Similar threads

Replies
14
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
44
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 21 ·
Replies
21
Views
1K
  • · Replies 3 ·
Replies
3
Views
9K
  • · Replies 3 ·
Replies
3
Views
2K