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p+p -> deutron+positron+neutrino(e)
The question is how much energy is released?
Q=(m_{p}+m_{p})-(m_{d}+m_{e^+}+0.26MeV)=(938+938)MeV-(938+939+0.51+0.26)MeV<0
So I don't understand how can energy be relesed? I found that Q for that reaction is 1.442MeV. What am I doing wrong?
The question is how much energy is released?
Q=(m_{p}+m_{p})-(m_{d}+m_{e^+}+0.26MeV)=(938+938)MeV-(938+939+0.51+0.26)MeV<0
So I don't understand how can energy be relesed? I found that Q for that reaction is 1.442MeV. What am I doing wrong?