Q01 are linearly independent vectors, so are....

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SUMMARY

The discussion centers on the proof that if vectors $v_1$, $v_2$, and $v_3$ are linearly independent, then their transformed counterparts $Av_1$, $Av_2$, and $Av_3$ remain linearly independent, provided that matrix A is invertible. The key argument presented involves applying the inverse of A, denoted as $A^{-1}$, to the equation $x_1Av_1 + x_2Av_2 + x_3Av_3 = 0$. This confirms that the linear independence of the original vectors is preserved under the transformation by an invertible matrix.

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karush
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Let A be invertible. Show that, if $\textbf{$v_i,v_2,v_j$}$ are linearly independent vectors, so are \textbf{$Av_1,Av_2,Av_3$}

https://drive.google.com/file/d/1OuHxfUdACbpK4E5aca2oBzdaxGR0IYKv/view?usp=sharing
p57.png


ok I think this is the the definition we need for this practice exam question,
However I tried to insert using a link but not successful
I thot if we use a link the image would always be there unless we delete its source

as to the question... not real sure of the answer since one $c_n$ may equal 0 and another may not

Anyway Mahalo...
 
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Yes, that is the definition of "linearly independent" you need. Now, what are you trying to prove?

You have "Show that, if $v_1$, $v_2$, $v_3$ are linearly independent, then so are $Av_1$, $Av_2$, $Av_3$" but what is "A"? If it is a general linear transformation this is not true. If A is an INVERTIBLE linear transformation then it is true and can be shown by applying $A^{-1}$ to both sides of$x_1Av_1+ x_2Av_2+ x_3Av_3= 0$.
 

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