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QCD gluon propagator in axial gauge, polarization sum

  1. Apr 1, 2011 #1
    Hi!

    I have a process with multiple feynman diagrams where gluon propagators occur. When I use an axial gauge for the gluon propagator, do I have to use the same n-vector for every propagator? Following this I wonder whether I can use the same n-vector for every polarization sum in axial gauge or have to take different ones.

    Thanks, Tobias

    gauge field propagator in general axial gauge:
    [tex]
    G_{\mu\nu}^{ab}(q,\alpha)=\frac{-i\delta^{ab}}{q^{2}}\left(-g^{\mu\nu}-\frac{q_{\mu}n_{\nu}+q_{\nu}n_{\mu}}{qn}+q_{\mu}q_{\nu}\frac{n^{2}+\alpha q^{2}}{(qn)^{2}}\right)
    [/tex]
     
  2. jcsd
  3. Apr 1, 2011 #2

    fzero

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    It seems pretty clear that in deriving the propagator above, one assumes that the vector [tex]n_\mu[/tex] doesn't vary with position. If it did, you would have to compute it's Fourier transform and the momentum space Feynman rules would be more complicated. Similarly, [tex]n_\mu[/tex] is independent of gauge indices, so there's no freedom to choose different values within a given computation.
     
  4. Apr 1, 2011 #3
    You can use a different gauge for each external gluon (though you have to be consistent between diagrams).

    You can use a different gauge for the internal gluons (different from the external legs), but each internal gluon must be in the same gauge. Changing the vector n is a form of gauge transformation.
     
    Last edited: Apr 1, 2011
  5. Sep 20, 2012 #4
    I'm fully aware that this post is over one year old, but could someone provide a source for the above statement or at least scetch if and why this is true?
     
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