QM: Time-Varying Forces & Potential Energy

[quasar987]

The SE is written in terms of a potential energy. It says, "given a particle in a region where the potential is V(,x,y,z), solve me if you want to know the probability density."

But not all forces can be represented by a potential energy. What does QM says, for exemple in the case of a particle in a time varying electric field?

 

[dextercioby]

Time varying potentials induce transitions among states on the time independent hamiltonian. That's what we have perturbation theory for.

Daniel.

 

[StatMechGuy]

In the case of a time-varying electric field, you would probably have to use the vector potential stuff as

<br /> \vec{E} = -\frac{1}{c} \frac{\partial \vec{A}}{\partial t} - \nabla \varphi<br />
<br /> \vec{B} = \nabla \times \vec{A}<br />

and then choose your vector potential accordingly.

edit: It's also interesting to note what happens if, say, your potential energy is not Hermitian. I recommend you explore that exercise a bit, as you get some interesting results regarding the normalization of the wave function. Also, it's important to note that most non-conservative forces (such as friction) are macroscopic, and, as far as I know, have no quantum analogs.

 

[quasar987]

But the potential in the SE is a scalar potential. What would you do with \vec{A}?

 

[Galileo]

The S.E. in 'fundamental form' is i\hbar \frac{\partial}{\partial t}|\Psi\rangle = H|\Psi\rangle.
You should always get H from the classical Hamiltonian. The S.E. you wrote down cannot accommodate for all situations.

In EM, the conjugate momentum \vec p of the position \vec r is not m\vec v but:
\vec p = m\vec v+q\vec A, and your Hamiltonian becomes:

H=\frac{1}{2m}\left(\vec p-q\vec A)^2+qU
where U and A are the potentials. The important thing is that they satisfy:

\vec E = -\vec \nabla U - \frac{\partial}{\partial t}\vec A
\vec B = \vec \nabla \times \vec A

(U and A are not unique. You have so-called gauge freedom. Different gauges will lead to the same physical results in EM and QM ofcourse. This is called gauge invariance).


By the way. At a fundamental level (microscopic scale), only conservative systems play a role anyway.