- #1
Matejxx1
- 72
- 1
1.given the equation a(3x2+2x+1)=4x-6x2-4 with the solutions x1 and x2
a) let a=0 without solving the equation calculate x1-3+x2-3
the correct answer is supposed to be -7/2
x1+x2=-b/a
x1*x2=c/a
The first thing I was that I put in "a" so,
0*(3x2+2x+1)=4x-6x2-4
0=4x-6x2-4...... here I multiplied the whole equation by -1
0=6x2-4x+4......here i divided the equation by 6
0=x2-4/6x+46
then I used the equation
1/x13+1/x23=(1/x1+1/x2)3 -3/x12x2 -3/x22x1
This is where I have no idea how to continue.I'm not even sure that what I have written is correct .If someone could help me solve this,I would really appreciate it. Thanks for reading .
a) let a=0 without solving the equation calculate x1-3+x2-3
the correct answer is supposed to be -7/2
Homework Equations
x1+x2=-b/a
x1*x2=c/a
The Attempt at a Solution
The first thing I was that I put in "a" so,
0*(3x2+2x+1)=4x-6x2-4
0=4x-6x2-4...... here I multiplied the whole equation by -1
0=6x2-4x+4......here i divided the equation by 6
0=x2-4/6x+46
then I used the equation
1/x13+1/x23=(1/x1+1/x2)3 -3/x12x2 -3/x22x1
This is where I have no idea how to continue.I'm not even sure that what I have written is correct .If someone could help me solve this,I would really appreciate it. Thanks for reading .