I Quantum entanglement in the MWI

Sayestu
Messages
30
Reaction score
0
TL;DR Summary
Does the MWI explain "spooky action at a distance"?
As far as I know, we don't understand the apparent faster-than-light "communication" between a measured particle and one entangled to it. Does the Many Worlds Interpretation explain this? Does it have anything else to say about entanglement?
 
Physics news on Phys.org
Sayestu said:
TL;DR Summary: Does the MWI explain "spooky action at a distance"?

As far as I know, we don't understand the apparent faster-than-light "communication" between a measured particle and one entangled to it.
There is no apparent faster-than-light communication involved in quantum entanglement.

Quantum entanglement is well understood within Quantum Mechanics. That some people may not be satisfied with this understanding is another matter.

Sayestu said:
Does the Many Worlds Interpretation explain this?
Not more than any other interpretation.
Sayestu said:
Does it have anything else to say about entanglement?
That's a broad question!
 
Sayestu said:
TL;DR Summary: Does the MWI explain "spooky action at a distance"?

As far as I know, we don't understand the apparent faster-than-light "communication" between a measured particle and one entangled to it.
Well, yes we do understand it perfectly well - assuming QM is correct. Bell's Theorem places constraints on any other proposed alternative, or extended, theory to replace QM. Loosely speaking you need instant communication or measurements which do not provide a definite outcome. "Every possibility happening at once" for instance. So you could argue that the apparent FTL communication is an artefact of rejecting indefiniteness. Not that the required indefiniteness is any easier to swallow than FTL.

Sayestu said:
Does the Many Worlds Interpretation explain this?
Sure. By postulating that the wave function doesn't collapse, MWI leaves multiple possible outcomes superposed. These develop into the separate worlds. This co-existence of outcomes satisfies one of the constraints of Bell's Theorem, indefiniteness. So there is no need to suppose there's any FTL communication. You don't need both.
Sayestu said:
Does it have anything else to say about entanglement?
Not specifically. MWI was developed to get rid of the collapse postulate. As such it affects all of QM.
 
Sayestu said:
Does the MWI explain "spooky action at a distance"?
Sort of. According to MWI, spooky action at a distance is just an illusion. Fundamentally, there is no action at a distance because there is no distance. According to MWI, we don't really live in a 3-dimensional world (that's just an illusion), so there is no distance in a 3-dimensional sense.
 
Demystifier said:
Sort of. According to MWI, spooky action at a distance is just an illusion. Fundamentally, there is no action at a distance because there is no distance. According to MWI, we don't really live in a 3-dimensional world (that's just an illusion), so there is no distance in a 3-dimensional sense.
This is valid up to a certain extent. It does not explain why we we do not have faster than light communication.
 
pines-demon said:
This is valid up to a certain extent. It does not explain why we we do not have faster than light communication.
It's up to you to explain why you think we might have FTL communication involved in quantum entanglement.
 
PeroK said:
It's up to you to explain why you think we might have FTL communication involved in quantum entanglement.
We do not have FTL communication. Call it whatever you want weak nonlocality, influence, or correlations, but it is not FTL signalling or FTL communication of energy/information.
 
  • Like
Likes kered rettop
Demystifier said:
According to MWI, we don't really live in a 3-dimensional world (that's just an illusion), so there is no distance in a 3-dimensional sense.
Do you mean the multi-dimensional world of phase space or something arcane, esoteric and ineffable? :oldbiggrin:
 
  • #10
kered rettop said:
Do you mean the multi-dimensional world of phase space or something arcane, esoteric and ineffable? :oldbiggrin:
or just Hilbert space.
 
  • Like
  • Skeptical
Likes kered rettop and PeroK
  • #11
kered rettop said:
Do you mean the multi-dimensional world of phase space or something arcane, esoteric and ineffable? :oldbiggrin:
Not exactly, but you are close. It can be the multi-dimensional world of configuration space (that's where the wave function in the position representation lives), or it can be the quantum Hilbert space.
 
  • Like
Likes physika and kered rettop
  • #12
pines-demon said:
This is valid up to a certain extent. It does not explain why we we do not have faster than light communication.
MWI explains quite easily why entanglement does not allow faster than light communication. It is because the agent who is supposed to communicate cannot choose at will which of the many branches of the wave function will be his branch.
 
  • Skeptical
  • Like
  • Informative
Likes mattt, pines-demon and kered rettop
  • #13
Demystifier said:
MWI explains quite easily why entanglement does not allow faster than light communication. It is because the agent who is supposed to communicate cannot choose at will which of the many branches of the wave function will be his branch.
I would just like to reassure pines-demon that, if he feels that Demystifier is missing out a few vital steps in the argument, he is not alone. :wink:
 
Last edited:
  • Like
Likes pines-demon
  • #14
kered rettop said:
I would just like to reassure pines-demon that, if he feels that Demystifier is missing out a few vital steps in the argument, he is not alone. :wink:
Those are left as an exercise for the reader. :oldbiggrin:
 
  • Love
  • Wow
  • Haha
Likes kered rettop, gentzen and pines-demon
  • #15
Demystifier said:
Those are left as an exercise for the reader. :oldbiggrin:
Sorry, I can't read.
 
  • #16
kered rettop said:
Sorry, I can't read.
Do you know why entanglement cannot be used for FTL signaling in standard QM?
 
  • Like
Likes PeterDonis and PeroK
  • #17
kered rettop said:
I would just like to reassure pines-demon that, if he feels that Demystifier is missing out a few vital steps in the argument, he is not alone. :wink:

Demystifier said:
Those are left as an exercise for the reader. :oldbiggrin:
I was just going to go deep into the semantics of MWI but I can live with this answer. :wink:
 
  • Wow
Likes kered rettop
  • #18
Demystifier said:
Do you know why entanglement cannot be used for FTL signaling in standard QM?
I sense a trap! I am tempted to say, The No-Communication Theorem, but as your question presumably harks back to post #12, I'll just say no.

[Mentors’ note: although this is not one of the best Wikipedia articles, it is a reasonably accurate proof of why entanglement does not allow FTL communication. We have a long thread hijack basically arguing about whether this proof is properly called the “No-Communication Theorem” has been removed from this thread]
 
Last edited by a moderator:
  • #19
kered rettop said:
I am tempted to say, The No-Communication Theorem
This is one of those cases where you should yield to temptation. :wink: The question specifically asked about "standard QM", and the no communication theorem is the answer for that. Different interpretations will tell different stories about why the no communication theorem is true (and post #12 gives a brief version of the story that the MWI might tell), but that's not "standard QM", that's interpretations.
 
  • Like
Likes Demystifier
  • #20
PeterDonis said:
This is one of those cases where you should yield to temptation.
Where have I heard that before? 😈
PeterDonis said:
The question specifically asked about "standard QM", and the no communication theorem is the answer for that.
Of course. Everybody knows that...
pines-demon said:
I seriously think that the theorem is not that popular and its origins are not well understood outside research groups.
... or maybe not everybody.
]
 
  • Haha
Likes pines-demon
  • #21
PeterDonis said:
This depends on which interpretation you use. In the MWI, measurement does not break any entanglements, it just creates more of them.
Does any interpretation single out entanglements as being "broken" by a measurement? I would have thought that they must assert that either any superposition is or that none is. Serious question.
 
  • #22
kered rettop said:
Does any interpretation single out entanglements as being "broken" by a measurement?
Any interpretation in which measurements have single outcomes will, since the resulting state will be a product state.
 
  • #23
PeterDonis said:
Any interpretation in which measurements have single outcomes will, since the resulting state will be a product state.
That's why I said "single out entanglements"! To my simple mind, "breaking" an entanglement is exactly the same as "collapse" of the wave function. Why have two words for the same thing, unless they are interpreted differently?

<sarcasm>Perhaps the ghosts who do all the work so quickly and over such long distances need to work in pairs? o0) </>
 
Last edited:
  • #24
kered rettop said:
That's why I said "single out entanglements"! To my simple mind, "breaking" an entanglement is exactly the same as "collapse" of the wave function. Why have two words for the same thing, unless they are interpreted differently?
Drat the system timeout! I really wanted to have another go at clarifying what I meant. Well, never mind. I'm clear on the physics and I don't want to go hair-splitting or getting bogged down in semantics. But I do feel that talking about "breaking the entanglement" suggests that something weird and wonderful is going on unrelated to "collapse of the wavefunction" - which is merely weird and wearisome. So I was wondering whether there are any interpretations, preferably within the canon of acceptable sources on PF, which tell a different story about state reduction in different scenarios? Probably not!
 
Last edited:
  • #25
kered rettop said:
That's why I said "single out entanglements"! To my simple mind, "breaking" an entanglement is exactly the same as "collapse" of the wave function. Why have two words for the same thing, unless they are interpreted differently?
You can model the breaking of entanglement with unitary evolution. You just need to include the pointer degrees of freedom.
 
  • #26
Morbert said:
You can model the breaking of entanglement with unitary evolution. You just need to include the pointer degrees of freedom.
Of course. Same as collapse of the wavefunction. Make the pointer big enough and you've got MWI. So was that a yes or a no? :oldbiggrin:
 
  • #27
kered rettop said:
So was that a yes or a no?
Still looking for straight answers in the interpretations subforum, I see? Sorry, they're not on offer there. :)

And seriously, I think you've just encountered another reason to be unhappy witrh natural language descriptions of entanglement. The math is clear and as you describe (just collapse, here of an non-factorizable superposition, but still just collapse), the non-technical math-free description starts off track ("we have two particles...") and never recovers.
 
  • #28
kered rettop said:
To my simple mind, "breaking" an entanglement is exactly the same as "collapse" of the wave function.
No, it isn't, because you can have wave function collapse even in cases where you are not measuring an entangled system. For example, if I measure the spin of a single free electron that isn't entangled with anything, I still have wave function collapse (in an interpretation where there is such a thing) when I detect the electron in one or the other output arm of the Stern-Gerlach device.
 
  • #29
Morbert said:
You can model the breaking of entanglement with unitary evolution. You just need to include the pointer degrees of freedom.
That doesn't break entanglement, it just spreads it out to include the pointer degrees of freedom. (And then to include the environment degrees of freedom, once you take decoherence into account.) I already posted about this.
 
  • #30
Nugatory said:
Still looking for straight answers in the interpretations subforum, I see? Sorry, they're not on offer there. :)
I wouldn't say they're exactly "on offer" anywhere else on PF :wink: Still, point taken.

Nugatory said:
And seriously, I think you've just encountered another reason to be unhappy witrh natural language descriptions of entanglement. The math is clear and as you describe (just collapse, here of an non-factorizable superposition, but still just collapse),
Thanks. It's nice to be told you've got something right, once in a while.

Edit - Darn, I spoke too soon. Thank you, PeterDonis.

Got to agree about language, though I might go a bit further and say the concepts themselves are alien to our natural way of thinking.
Nugatory said:
the non-technical math-free description starts off track ("we have two particles...") and never recovers.
Ah, just when I thought I was following you! What's wrong with "we have two particles"? It may be that in QFT, the number of particles can be uncertain but surely not in good old vanilla QM?
 
Last edited:
  • #31
PeterDonis said:
No, it isn't, because you can have wave function collapse even in cases where you are not measuring an entangled system. For example, if I measure the spin of a single free electron that isn't entangled with anything, I still have wave function collapse (in an interpretation where there is such a thing) when I detect the electron in one or the other output arm of the Stern-Gerlach device.
Didn't I mention this? Must have edited it out thinking it was too obvious to be worth saying. Life being short and all that. Yes, obviously, the words do mean different things and you can't break the entanglement of a system that is not entangled because that would be silly. But they still refer to the same putative physical process.
 
  • Like
Likes pines-demon
  • #32
kered rettop said:
Ah, just when I thought I was following you! What's wrong with "we have two particles"?
In the math we don’t have two particles. We have one quantum system described by one wave function, it just so happens that the two possible measurements (spin/polarization at one detector, spin/polarization at the other) we might perform on this system happen at different places. Because of the spatial separation our classical intuition demands that we think in terms of two distinguishable particles in two different places… and it’s a short step from there to spooky action at a distance and all the other entanglement misunderstandings that show up in our B-level threads.
 
  • Like
Likes PeroK and Lord Jestocost
  • #33
Conjecture: It does not matter what terminology you use to describe entanglement, there is always one interpretation in which your description is wrong.

Corollary: you might use math to avoid this problem, but you will still get criticism for how you call or describe your equations and variables.

Of course this does not exclude being wrong in all interpretations. :oldbiggrin:
 
  • Like
Likes kered rettop
  • #34
PeterDonis said:
That doesn't break entanglement, it just spreads it out to include the pointer degrees of freedom. (And then to include the environment degrees of freedom, once you take decoherence into account.) I already posted about this.
I am referring to the entanglement in the microscopic system. E.g. Consider a two-particle system in the Bell state ##|\Phi^+_{12}\rangle\langle\Phi^+_{12}|## and a joint (and ideal and nondestructive) spin measurement represented by ##\frac{\hbar^2}{4}\sigma^1_x\sigma^2_z## (I.e. a measure of spin-x on particle 1 and spin-z on particle 2). If we include the pointer degrees of freedom, a unitary evolution through the measurement process and a trace over the pointer degrees of freedom will yield the two-particle system in the unentangled state ##\rho_1\otimes\rho_2##.

[edit]- Rewrote last bit, which was unclear
 
Last edited:
  • #35
Morbert said:
I am referring to the entanglement in the microscopic system
Unitary evolution doesn't break that either. The microscopic entanglement will no longer be maximal, because other degrees of freedom are involved, but it doesn't go away either.

Morbert said:
a trace over the pointer degrees of freedom
Throws away precisely the information you need to see that the entanglement between the microscopic degrees of freedom is still there. To properly evaluate this question you need to look at the actual pure state of the entire system; you can't trace out anything.
 
  • Like
Likes kered rettop
  • #36
Nugatory said:
In the math we don’t have two particles.

Correct me if I'm wrong, but don't we have a sum of products like |H>|V> + |V>|H> ?
If not two particles, what do the kets refer to?
Or would you say that |H>|V> + |V>|H> is actually wrong and we should always write |HV> + |VH>?

Nugatory said:
We have one quantum system described by one wave function, it just so happens that the two possible measurements (spin/polarization at one detector, spin/polarization at the other) we might perform on this system happen at different places. Because of the spatial separation our classical intuition demands that we think in terms of two distinguishable particles in two different places… and it’s a short step from there to spooky action at a distance and all the other entanglement misunderstandings that show up in our B-level threads
Not only there. :oldbiggrin:

I tend to think of the system as two particles largely because I can definitely prepare two photons which do not behave as a single unit, and also an entanglement which behaves as two photons in every respect
except, arguably, the entangled property. So rather than adopt a really weird ontology for the little hard lumps :oldbiggrin: I look to the "get-outs" of Bell's Theorem.
 
  • #37
@PeterDonis I don't know if our disagreement is substantive. I.e. I don't want to argue over the specifics of "to break" so I'll leave it there.
 
  • #38
Sayestu said:
TL;DR Summary: Does the MWI explain "spooky action at a distance"?

As far as I know, we don't understand the apparent faster-than-light "communication" between a measured particle and one entangled to it. Does the Many Worlds Interpretation explain this? Does it have anything else to say about entanglement?
MWI doesn't explain entanglement in terms of concepts fundamental to quantum mechanics because MWI simply assumes the quantum formalism is fundamental. And, it really doesn't resolve the mystery of entanglement because there is still a nonlocality associated with entanglement in MWI. It's easy to see this nonlocality in entangled spin measurements. Suppose Alice and Bob are switching very fast between measurement options so that Alice's(Bob's) outcome is spacelike related to Bob's(Alice's) setting. Sometimes Alice and Bob happen to choose the same setting and sometimes they choose different settings. When they choose the same setting the wavefunction splits into the two possible outcomes (possible worlds), i.e., uu and dd, and when they choose different settings the wavefunction splits into all four possible outcomes (possible worlds), uu, ud, du, and dd. How does the wavefunction know the possibilities? Here is what Vaidman writes in SEP https://plato.stanford.edu/archives/fall2021/entries/qm-manyworlds/:

Although the MWI removes the most bothersome aspect of nonlocality, action at a distance, the other aspect of quantum nonlocality, the nonseparability of remote objects manifested in entanglement, is still there. A “world” is a nonlocal concept. This explains why we observe nonlocal correlations in a particular world.
 
  • Like
Likes PeroK and DrChinese
  • #39
RUTA said:
MWI doesn't explain entanglement in terms of concepts fundamental to quantum mechanics because MWI simply assumes the quantum formalism is fundamental. And, it really doesn't resolve the mystery of entanglement because there is still a nonlocality associated with entanglement in MWI. It's easy to see this nonlocality in entangled spin measurements. Suppose Alice and Bob are switching very fast between measurement options so that Alice's(Bob's) outcome is spacelike related to Bob's(Alice's) setting. Sometimes Alice and Bob happen to choose the same setting and sometimes they choose different settings. When they choose the same setting the wavefunction splits into the two possible outcomes (possible worlds), i.e., uu or dd, and when they choose different settings the wavefunction splits into all four possible outcomes (possible worlds), uu, ud, du, or dd. How does the wavefunction know the possibilities? Here is what Vaidman writes in SEP https://plato.stanford.edu/archives/fall2021/entries/qm-manyworlds/:
Easy! The two-electron wave function does not split so it does not need to know.

When it interacts with the detector, the resultant entanglement does know the setting.
 
  • Like
Likes pines-demon
  • #40
RUTA said:
MWI doesn't explain entanglement in terms of concepts fundamental to quantum mechanics because MWI simply assumes the quantum formalism is fundamental. And, it really doesn't resolve the mystery of entanglement because there is still a nonlocality associated with entanglement in MWI. It's easy to see this nonlocality in entangled spin measurements. Suppose Alice and Bob are switching very fast between measurement options so that Alice's(Bob's) outcome is spacelike related to Bob's(Alice's) setting. Sometimes Alice and Bob happen to choose the same setting and sometimes they choose different settings. When they choose the same setting the wavefunction splits into the two possible outcomes (possible worlds), i.e., uu and dd, and when they choose different settings the wavefunction splits into all four possible outcomes (possible worlds), uu, ud, du, and dd. How does the wavefunction know the possibilities? Here is what Vaidman writes in SEP https://plato.stanford.edu/archives/fall2021/entries/qm-manyworlds/:
What do you mean by "how the wavefunction knows the possibilities?" The possible outcomes are clear if you write the state, it depends on the settings. The state is just following Schrödinger's equation.

Also, what does even Vaidman mean when he says that a "World is a nonlocal concept". Is it just that an observer in a world predicts non-local probabilities? Or does he mean something related to the concept of World by itself?
 
  • Like
Likes kered rettop
  • #41
RUTA said:
the wavefunction splits
More precisely, the entanglement spreads to include the detector (and then to include the environment once we take decoherence into account). There is no "split"; the possibilities you refer to are already there in the wave function, they just don't include the detector and the environment until after the measurement.
 
  • #42
pines-demon said:
what does even Vaidman mean when he says that a "World is a nonlocal concept"
He means that the wave function includes entangled degrees of freedom that are spatially separated.
 
  • #43
pines-demon said:
Also, what does even Vaidman mean when he says that a "World is a nonlocal concept". Is it just that an observer in a world predicts non-local probabilities? Or does he mean something related to the concept of World by itself?
His text immediately continues with nonlocal correlations after his „world is a nonlocal concept“. Therefore, he doesn‘t mean that the concept of world would be inherently nonlocal. Just that it allows nonlocality.
 
  • Like
Likes pines-demon
  • #44
pines-demon said:
Also, what does even Vaidman mean when he says that a "World is a nonlocal concept". Is it just that an observer in a world predicts non-local probabilities? Or does he mean something related to the concept of World by itself?
Re/ a world as a concept: According to Vaidman, the only physical process is a universal wavefunction evolving according to a relativistic generalization of the Schroedinger equation , and he describes a world as a "human concept which is supposed to help explaining our experience" i.e. a concept relating the universal wavefunction to our experiences. The decomposition of the wavefunction into states tracking our experiences, where all macroscopic objects are localized, is not privileged over any other decomposition.

Re/ a world as nonlocal: Vaidman notes that the entanglement/nonseparability of the wavefunction means the worlds each observer conceptualizes will have connections, and these connections give the illusion of action at a distance
https://arxiv.org/abs/1501.02691
What makes this situation [the GHZ experiment] nonlocal is that while all four different local options are present for all observers, i.e., there are four Everett worlds for Alice, and separately for Bob and for Charley, we do not have 64 worlds. Specifying Everett worlds of two observers fixes the world of the third. This connection between local worlds of the observers is the nonlocality of the MWI.

[...]

Is there any possibility of action at a distance in the framework of the MWI? Obviously, at the level of the physical universe that includes all the worlds, local action cannot change anything at remote locations. However, a local action splits the world, which is a nonlocal concept, and local actions can bring about splitting to worlds that differ at remote locations. Thus, an observer for whom only his world is relevant has an illusion of an action at a distance when he performs a measurement on a system entangled with a remote system.
 
  • Like
Likes pines-demon and gentzen
  • #45
As we are talking about MWI. One thing that does not click to me appears when discussing entanglement that is not a symmetrical Bell state. What about other kinds of entanglements?

Suppose we have the state:
$$|\Psi\rangle = \sqrt{\frac34}|00\rangle+\frac{1}{2}|11\rangle$$

How does a world "split" in order to make the percentages right? Note that even with repeated measurements, the answer seems to be 2 at each split. Is there some kind of densities of worlds?
 
  • #46
pines-demon said:
How does a world "split" in order to make the percentages right?
The "splitting" (which is not a good term, see my previous post on this) does not depend on the coefficients of the terms; there is just one "world" for each term.

The "weights" of the worlds (the coefficients of each term) and what they mean is an open issue with the MWI. Various MWI proponents have expressed viewpoints on it, but AFAIK none of them has gotten general acceptance.
 
  • #47
pines-demon said:
As we are talking about MWI. One thing that does not click to me appears when discussing entanglement that is not a symmetrical Bell state. What about other kinds of entanglements?

Suppose we have the state:
$$|\Psi\rangle = \sqrt{\frac34}|00\rangle+\frac{1}{2}|11\rangle$$

How does a world "split" in order to make the percentages right?
The amplitude of the world-states must be the same as that of the parent components in the entanglement, namely $$ \sqrt{\frac34} and \frac{1}{2}$$
pines-demon said:
Note that even with repeated measurements, the answer seems to be 2 at each split.
There's only one split. The 00 world for instance is |00> and nothing else so it can't be split by a second measurement.

pines-demon said:
Is there some kind of densities of worlds?
Of course. The amplitudes determine the probabilities via the Born Rule: 3/4 and 1/4 in your example.
 
  • #48
kered rettop said:
Of course. The amplitudes determine the probabilities via the Born Rule: 3/4 and 1/4 in your example.
"Of course" is somewhat optimistic as regards the MWI, since how to account for the Born Rule (and indeed how to formulate a meaningful concept of probability at all) in the context of the MWI is a key open issue.
 
  • Like
  • Skeptical
Likes DrChinese and kered rettop
  • #49
PeterDonis said:
"Of course" is somewhat optimistic as regards the MWI, since how to account for the Born Rule (and indeed how to formulate a meaningful concept of probability at all) in the context of the MWI is a key open issue.
As far as I can see, Vaidman's argument amounts to a bit of hand waving and saying that probability is an illusion. The examples (in the various recent threads on this) always involve equally likely basic events, where to some extent probability can be waved away. It's not clear, however, that an event like radioactive decay can be explained in this way. The basic events of decay or not decay over a given time period are generally not equally likely. I don't see how probability or a weighting of worlds in the model can be avoided.
 
  • #50
Here is a (pop sci) video, arguing for a Principle of indiference as a possible solution of the derivation of the Born rule in MWI. I know is pop sci but you have a link to a pdf by Taha Dawoodbhoy (that is itself a derivation of the concept from Zurek and Carroll) that explains it in more detail.
 
  • Informative
  • Like
Likes physika and PeroK
Back
Top