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This simple calculation bases the quantum effects of gravity on the electromagnetic frequency across ½ the Compton wavelength of the electron.
2.998 x 10^8 ms-1
½ (2.4263 x 10^-12 m) = 2.471 x 10^20 s-1
This is multiplied by Planck’s constant to arrive at energy in joules.
(2.471 x 10^20 s-1) (6.626 x 10^-34 kgm2s-1) = 16.373 x 10^-14 kgm2s-2
This value is multiplied by the square of the radius of a planet like Earth and the product divided into Planck mass.
2.1767 x 10^-8 kg
(16.373 x 10^-14 kgm2s-2) (6.378 x 10^6 m)2 = .003268 x 10^-6 m-4s2
In the meantime, the number of Planck lengths along a geometric line across the Schwartzchild radius of the planet is determined. First, the Schwartzchild radius:
2(6.673 x 10^-11 m3kg-1s-2) (5.974 x 10^24 kg)
SRearth = (2.998 x 10^8 ms-1)2 = 8.87 x 10^-3 m
The Schwartzchild radius is divided by Planck length to get the total number of lengths along the planet radius.
8.87 x 10^-3 m
1.616 x 10^-35 m = 5.489 x 10^32
This value is energized in joules by multiplying by the energy equivalent of the electron mass.
(5.489 x 10^32) (8.187 x 10^-14 kgm2s-2) = 44.938 x 10^18 kgm2s-2
This value is multiplied by that arrived at above in the first part.
(.003268 x 10^-6 m-4s2) (44.938 x 10^18 kgm2s-2) = 1.469 x 10^11 kgm-2
This value multiplied by G predicts the standard acceleration of gravity at 6,378,000 radial meters and a mass of 5.974 x 10^24 kg.
(6.673 x 10^-11 m3kg-1s-2) (1.469 x 10^11 kgm-2) = 9.8 ms-2
As an additional for instance, it accurately predicts g on Venus to be
8.8 ms-2 at a radius of 6,052,000 meters and mass of 4.869 x 10^24 kg. Actually, the data of any planet plugged into the formula above yields answers at 100% the accuracy rate of the classical g = Gm/r2.
(this is copyrighted material) © March 2004
This simple calculation bases the quantum effects of gravity on the electromagnetic frequency across ½ the Compton wavelength of the electron.
2.998 x 10^8 ms-1
½ (2.4263 x 10^-12 m) = 2.471 x 10^20 s-1
This is multiplied by Planck’s constant to arrive at energy in joules.
(2.471 x 10^20 s-1) (6.626 x 10^-34 kgm2s-1) = 16.373 x 10^-14 kgm2s-2
This value is multiplied by the square of the radius of a planet like Earth and the product divided into Planck mass.
2.1767 x 10^-8 kg
(16.373 x 10^-14 kgm2s-2) (6.378 x 10^6 m)2 = .003268 x 10^-6 m-4s2
In the meantime, the number of Planck lengths along a geometric line across the Schwartzchild radius of the planet is determined. First, the Schwartzchild radius:
2(6.673 x 10^-11 m3kg-1s-2) (5.974 x 10^24 kg)
SRearth = (2.998 x 10^8 ms-1)2 = 8.87 x 10^-3 m
The Schwartzchild radius is divided by Planck length to get the total number of lengths along the planet radius.
8.87 x 10^-3 m
1.616 x 10^-35 m = 5.489 x 10^32
This value is energized in joules by multiplying by the energy equivalent of the electron mass.
(5.489 x 10^32) (8.187 x 10^-14 kgm2s-2) = 44.938 x 10^18 kgm2s-2
This value is multiplied by that arrived at above in the first part.
(.003268 x 10^-6 m-4s2) (44.938 x 10^18 kgm2s-2) = 1.469 x 10^11 kgm-2
This value multiplied by G predicts the standard acceleration of gravity at 6,378,000 radial meters and a mass of 5.974 x 10^24 kg.
(6.673 x 10^-11 m3kg-1s-2) (1.469 x 10^11 kgm-2) = 9.8 ms-2
As an additional for instance, it accurately predicts g on Venus to be
8.8 ms-2 at a radius of 6,052,000 meters and mass of 4.869 x 10^24 kg. Actually, the data of any planet plugged into the formula above yields answers at 100% the accuracy rate of the classical g = Gm/r2.
(this is copyrighted material) © March 2004