Question about a Flip Flop circuit

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SUMMARY

The discussion centers on the operation of a NAND latch and its behavior in a Flip Flop circuit. Specifically, it clarifies how the next state (Q+) is determined using the expression Q+ = x XOR Q, where S and R inputs influence the output Q. The user expresses confusion regarding the relationship between the inputs and the output state, particularly in the context of a NAND latch configuration. The explanation confirms that when S=1, the circuit sets Q to 0, and the state transitions are clocked accordingly.

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Salman Ali
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Hello! I am confused in a question I found on youtube. I have uploaded the screen shots.
He told that with respect to S and R we have to write the change from Q to Q+( next state). But I am not getting it. How he wrote Q+ states?Is he considering that when S=1 , we have to set the circuit i.e on Q , 1 will be stored and the circuit will be set and vice versa? But this is a nand latch right? S is above R and infront of S there is Q. So it is a nand latch in which when S=1 Q is 0 . Thanks
 

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Last edited:
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When the F/F is clocked the state of S and R are copied through to Q and Qbar respectively.
If x is different to Q then the next state will be 1, which is the XOR function.
Answer (c); Q+ = x XOR Q.
 

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