Chemistry Question about balancing a reaction

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The reaction H3PO4(aq) + KMnO4(aq) + H2SO4(aq) → H3PO4(aq) + MnSO4(aq) + K2SO4(aq) + H2O(l) cannot be balanced because it lacks a corresponding oxidation process for the reduction of manganese. The presence of H3PO4 on both sides complicates balancing, as it must remain unchanged. The five elements involved—K, Mn, H, S, and O—require matching on both sides, leading to five equations but only four degrees of freedom for balancing. This results in an unsolvable situation, akin to trying to satisfy contradictory equations. Therefore, the reaction as presented is not valid for balancing.
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Homework Statement
balancing a reaction
Relevant Equations
H3PO4(aq) + KMnO4(aq) + H2SO4(aq) → H3PO4(aq) + MnSO4(aq) + K2SO4(aq) + H2O(l)
hi,

I was asked to balance this reaction :

H3PO4(aq) + KMnO4(aq) + H2SO4(aq) → H3PO4(aq) + MnSO4(aq) + K2SO4(aq) + H2O(l)

can I get some help? why we can't balance this reaction? and what can we say about a reaction that has the same compound as a reagent and a product?
thank you
 
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That's not a reaction. Mn is being reduced, but nothing is being oxidised. Have you copied it correctly?
 
yes, our teacher insists that there is no mistake in the reaction
 
I assure you there is. What is the permanganate oxidising?
 
You were told exactly the same at other forum, weren't you?
 
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yuval12 said:
Relevant Equations:: H3PO4(aq) + KMnO4(aq) + H2SO4(aq) → H3PO4(aq) + MnSO4(aq) + K2SO4(aq) + H2O(l)

why we can't balance this reaction?
Ignoring H3PO4(aq) which needs to stay balanced (only chemical with P) you have five elements, K, Mn, H, S, O, that have to match on both sides -> 5 equations. You have five chemicals there, which gives you four degrees of freedom to try to balance the equation (the fifth is just an overall scaling of the reaction). There is no solution to that problem here. It's like trying to solve "x=5 and x=7". Find x such that both equations are satisfied. You can't.
 
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