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Question about binary counter with jk flip-flops

  1. Nov 17, 2009 #1
    Hi,

    Let's say i want to make a binary counter using jk-flip-flops that counts 1,3,5,7,1...

    Then i'd use the excitation table for the jk-flip-flop to determine the next state.

    The next step would be to use karnaugh-maps to minimize the j and k columns.

    My question is: Do i need to record, in the karnaugh-maps, when j or k is zero or only when they are at logic 1 ?
     
  2. jcsd
  3. Nov 17, 2009 #2
    you wont get zero for both j and k.. You will have either "zero" or "one" or "dont care(X)"..
    So therefore you can record k-map according to i/p's.. I hope you know, that we can pair,quad,octal "1" with "X".
     
  4. Nov 17, 2009 #3
    Hi,

    So if one column for either J or K turn out to have only don't care or zero, i can just ignore it?
     
  5. Nov 17, 2009 #4
    You will get a 1 at some point for sure.. Try solving one problem!
    I haven't encountered having only 0 or X situation.
     
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