Question about concave mirrors

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    Concave Mirrors
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SUMMARY

A concave mirror with a radius of curvature of 1.4 m and a candle located 3.4 m from the mirror requires the correct application of mirror equations to determine the image location. The discussion emphasizes the importance of using the correct formula, specifically noting that the distance of the object (do) and the distance of the image (di) are not equal. Ray tracing is recommended as a visual method to accurately find the image position. The focal length must be correctly identified to apply the mirror equation effectively.

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  • Understanding of concave mirrors and their properties
  • Familiarity with the mirror equation and focal length concepts
  • Basic knowledge of ray tracing techniques in optics
  • Ability to interpret physics problems involving geometric optics
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  • Study the mirror equation: 1/f = 1/do + 1/di
  • Learn how to perform ray tracing for concave mirrors
  • Explore the relationship between object distance, image distance, and focal length
  • Review examples of concave mirror problems in physics textbooks
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Students studying physics, particularly those focusing on optics, as well as educators teaching concepts related to concave mirrors and image formation.

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Homework Statement


A concave mirror with a radius of curvature
of 1.4 m is illuminated by a candle located on
the symmetry axis 3.4 m from the mirror.
Where is the image of the candle? Answer
in units of m.


Homework Equations





The Attempt at a Solution


I tried plugging in the numbers into the di=do equation but i think that's wrong out of this world.lol
 
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Why do you feel the need to plug numbers into an equation? Why not do a ray tracing diagram and find out where the image is formed?

A ray from the bottom of the candle, situated on the axis of symmetry will be reflected back along that axis.
Then consider ray from the top of the candle parallel to the axis. Where will that ray be reflected?
Then consider a ray from the top of the candle passing through the focal point of the mirror. Where will that ray be reflected?
When you've done all that you'll know where the image is formed.Then measure off the answer from the drawing.
 
Aneadra said:
I tried plugging in the numbers into the di=do equation but i think that's wrong out of this world.lol

Using an equation should work, and is in fact how many physics problems are solved. But you do need to use the correct equation.

do=di is wrong, since they are not necessarily equal to each other. Can you not find the correct equation in your notes or textbook? If not, look here:

https://www.physicsforums.com/library.php?do=view_item&itemid=148
A curved mirror acts like a lens, but you need to be careful about what you use for f.
 

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