Undergrad Question about friction in situation where interface slip occurs

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The discussion centers on the mechanics of friction at the interface between two components when slip occurs. When the external force exceeds the friction force, slip initiates, leading to a new static equilibrium state once motion stops. In this state, static friction applies if there is no further slip, even if the object remains deformed. The "stick-slip mechanism" is referenced as a theoretical framework for understanding these dynamics, though predicting outcomes quantitatively for specific objects remains challenging. The need for quantifying stress, strain, and deformation in these scenarios is emphasized as a complex problem.
ohmyshoulder
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Hello, I have question about friction at inteface between two component

slip occurs at interface when external force bigger than friction force(= normal reaction force * static friction coefficient)

After slip occured, component motion stopped and got new static equlibrium state

In this state, how force applied at interface? static friction applied? dynamic friction applied? or other case?
 

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ohmyshoulder said:
... got new static equlibrium state

In this state, how force applied at interface? static friction applied?
If there is no slip anymore, but the object is still deformed, then you have static friction.
 
A.T. said:
If there is no slip anymore, but the object is still deformed, then you have static friction.
Thank you for applying!

I got theory about this problem named "stick-slip mechanism"

It's so hard problem to understand.

I would have to study a lot

thank you
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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