Why Does Inertia Affect Movement of Coin on Paper?

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Inertia affects the movement of a coin on paper due to the differences between static and kinetic friction. When the paper is pulled quickly with a high force, the coin remains in place because it doesn't have enough time to overcome static friction. Conversely, pulling the paper slowly allows the coin to accelerate and move with it, as the lower force provides more time for the coin to respond. The static friction coefficient is higher than the kinetic friction coefficient, which explains why the coin resists movement under rapid force. Understanding the relationship between force, time, and friction clarifies the observed behavior of the coin.
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The Coin(Green) in lying on a paper which is lying on a box.When I pull the paper with a higher force so that I could remove it easily,the coins stays about the same place.
When I remove the paper slowly,the coin comes with the paper.
Why?

I think that objects can react(Move) to smaller forces easily but for larger forces,it doesn't.
What do you think?
 

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adjacent said:
Why?
Because the coefficient of static friction is higher than the coefficient of kinetic friction.

adjacent said:
I think that objects can react(Move) to smaller forces easily but for larger forces,it doesn't.
What do you think?
No, that is wrong.
 
DaleSpam said:
Because the coefficient of static friction is higher than the coefficient of kinetic friction.
What?I don't Understand
 
In addition to the difference between static and kinetic friction, there is the difference between fast and slow.

If you pull the paper with high force, you pull it fast. There is not much time for the coin to speed up. If you pull the paper with low force, you pull it slow. There is more time for the coin to speed up.

The momentum delivered by a fixed force over a time interval is proportional to the duration of that interval.
 
Static friction force is given by f_s\le\mu_s N and kinetic friction force is given by f_k=\mu_k N. In both cases N (the normal force) is the same, so ##f_s## (the friction force without slipping) can be larger than ##f_k## (the friction force with slipping).
 
Oh .Now I Understood.Thanks
 
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