Question about relative speeds.

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In a collision between a moving object with speed v_1 and mass m_1 and a stationary object with mass m_2, momentum conservation leads to the equation m_1 v_1 = (m_1 + m_2)v_2 for the final speed v_2. Analyzing from the rest frame of m_1 suggests that m_2 moves towards it at speed v_1, leading to a different equation m_2(-v_1) = (m_1 + m_2)v_2. The perceived discrepancy arises from using different reference frames, which results in different final speeds. However, when transforming the results back to the original frame by adding v_1, the speeds align, confirming the consistency of momentum conservation across frames. This illustrates the importance of reference frames in analyzing collisions.
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Lets say I have a moving object that has speed v_1
and mass m_1 and it collides with a more massive object of
mass m_2 And this mass is at rest and when they collide they stick together.
If I use momentum conservation I would get
m_1 v_1=(m_1+m_2)(v_2) and v_2 is the speed after the collision
but what if I wanted to analyze this from the rest frame of m_1
It would look as if the more massive object was moving at me at a speed v_1
So now I would have m_2(-v_1)=(m_1+m_2)(v_2) the final speeds would be different in those 2 cases so what's wrong with my reasoning.
 
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The final speeds would indeed be different because you are using a different reference frame. To check to make sure there is no conflict, compare the before and after speeds of each object. The difference should be the same regardless of which frame you choose.
 
port31 said:
So now I would have m_2(-v_1)=(m_1+m_2)(v_2) the final speeds would be different in those 2 cases so what's wrong with my reasoning.
If you now transform your answer to the original frame (by adding v_1) you'll find that the speeds match.
 
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