Question about something reaching exactly +

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The discussion centers on understanding +2G acceleration during a turn, specifically in terms of tangential and normal acceleration. Normal (centripetal) acceleration is calculated using the formula v^2/r, where v is velocity and r is the radius of the turn. The equation suggests that if normal acceleration equals 2g, then 2g can be expressed as v^2/r. It is clarified that g represents magnitude only, without a negative sign. The explanation ultimately helps clarify the concept of acceleration in the context of circular motion.
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[SOLVED] Question about something reaching exactly +

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Sorry, I accidentally hit the enter button. Anyways my question is about something reaching exactly +2G acceleration on a turn. I tried asking my friends and teacher about it but it didn't exactly make sense the way they explained it. I just want to know what that means to have a +2g acceleration when turning
 
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Tangential or normal? I think you'll have to explain more about what your friends and teachers explained and express that in the form of a question.
 
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I think normal.
 
Normal (centripetal) acceleration is given by v^2/r, where r is the radius of the turn and v is the velocity. If that's equal to 2g, then 2g=v^2/r.
 
Oh okay. That makes sense now. So that would mean that 2(-9.81m/s^2) = v^2/r right?
 
Right. Except I wouldn't put a minus sign on g in this context. g is just a magnitude, not a direction.
 
Oh okay. Thanks so much!
 
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