Question about squaring velocity

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In the equation v^2 = V0^2 + 2a(x), squaring the velocities V and V0 results in positive values regardless of their initial signs. The negative sign does not affect the outcome of the squared terms, as squaring any real number, including negative values, yields a positive result. Therefore, both V^2 and V0^2 will always be positive quantities. This confirms that the negative sign is irrelevant in the context of squaring these velocities. Understanding this principle is essential for correctly applying the equation in physics problems.
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When using the equation v^2=V0^2 + 2a (x)...

If V or V0 is negative, does it become positive after squaring? (Basically, is the negative sign in the bracket or outside)?

Thanks in advance.
 
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The velocities will be positive when squared.
 
ZenOne said:
If V or V0 is negative, does it become positive after squaring?
V^2 and V0^2 will be positive quantities even when V or V0 is negative.
 
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