Question about Steradian and Radian for Compton.s Photons

  • Thread starter Thread starter abotiz
  • Start date Start date
  • Tags Tags
    Photons
Click For Summary

Homework Help Overview

The discussion revolves around the relationship between the number of Compton scattered photons measured in steradians and radians, specifically comparing measurements at angles of 90 degrees and 150 degrees.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of steradian and radian, questioning how these definitions relate to the number of scattered photons. There are attempts to derive relationships using differential cross-section formulas and angular measurements.

Discussion Status

Participants are actively engaging with the definitions and mathematical relationships involved. Some guidance has been offered regarding the formulas used, but there is no explicit consensus on the correct interpretation or application of the definitions.

Contextual Notes

There is mention of literature being used for definitions, and some participants express uncertainty about whether the definitions apply universally or in special cases. The discussion reflects a lack of complete information regarding the definitions of steradian and radian in this context.

abotiz
Messages
72
Reaction score
0

Homework Statement



In an experiment there was found equal compton scattered photons per steradian in the direction 150* as in 90*

Homework Equations



What relation in number of scattered photons in 150* and 90* would you get if you define number of photons per radians instead?

The Attempt at a Solution



I feel that this one is easy, but I don't know how to start with this.

Thanks!
 
Physics news on Phys.org
hi abotiz! :smile:

(have a degree: ° :wink:)

be logical …

start with the definition …

what is the definition of steradian? :wink:
 
[tex]\stackrel{d\sigma}{d\theta}[/tex]=[tex]\stackrel{d\sigma}{d\Omega}[/tex]*[tex]\stackrel{d\Omega}{d\theta}[/tex]

where [tex]\stackrel{d\Omega}{d\theta}[/tex] = 2[tex]\pi[/tex]sin[tex]\theta[/tex]

so the answer is sin90/sin150 i.e = 2

Right?

Thanks
 
Last edited:
hi abotiz! :smile:

(just got up :zzz: …)
abotiz said:
[tex]\stackrel{d\sigma}{d\theta}[/tex]=[tex]\stackrel{d\sigma}{d\Omega}[/tex]*[tex]\stackrel{d\Omega}{d\theta}[/tex]

where [tex]\stackrel{d\Omega}{d\theta}[/tex] = 2[tex]\pi[/tex]sin[tex]\theta[/tex]

so the answer is sin90/sin150 i.e = 2

Right?

Thanks

sorry, i don't understand that at all :confused:

what are you using as the definition of steradian?
 
Hi!

I found that definition in the Literature we are using.

Seems to be derived from [tex]\sigma[/tex] = [tex]\int\stackrel{d\sigma}{d\Omega}[/tex]*[tex]\Omega[/tex] ( total scattering cross section )

Anyways, I think my answer is right, perhaps the definitions we are using is based for a special case or something, which I don't know anything about :-p

Thanks
 
That's the formula for the integral of the differential cross-section (σ is ordinary area in m2, Ω is angular area in steradians) …

where do radians come into it? :confused:
 
Beats me.

But its not that weird, if you would take the derivative of that equation and divide both side with the differential angle, or what you call it ( dtheta) you would get the equation I used. Anyways, Thanks
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
7
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K