Question about the derivative of e^x

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    Derivative E^x
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Discussion Overview

The discussion revolves around the derivative of the function e^x, exploring whether it is exact and the nature of the constant e. Participants examine the mathematical definitions and properties related to e and its derivative, including limits and logarithmic functions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions whether the derivative of e^x is exact, seeking clarification on the precision of the constant e.
  • Another participant explains that the derivative of g^x, where g is any number, is given by ln(g) g^x, and discusses the significance of the number e, which is defined such that ln(e) = 1.
  • A different participant asserts that the number e is exact and that the derivative of e^x is exactly e^x, expressing appreciation for the function's properties.
  • Another participant highlights the unique characteristic of e^x, noting that differentiating or integrating it returns the same function, while also questioning the origins of its definition.

Areas of Agreement / Disagreement

Participants generally agree that the derivative of e^x is exactly e^x and that the constant e is exact. However, there is some exploration of the definitions and implications surrounding these concepts without a formal resolution of all questions raised.

Contextual Notes

Some discussions involve the limits and definitions of e, which may depend on specific mathematical interpretations or contexts. The nature of logarithmic functions and their relationship to the derivative is also a point of exploration.

Who May Find This Useful

This discussion may be useful for students and educators in mathematics, particularly those interested in calculus and the properties of exponential functions.

The_ArtofScience
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I've been drawn to this expression for a long time.

Anyway, my question is - is the derivative of e^x exact? That is with absolute precision, the derivative of e^x is EXACTLY e^x?

Sorry if this seems like a silly question, I would really like to know if my math instructor is right on this one

I remember the argument:

lim h-->0 e^x+h - e^x/ h

What about the constant e? Is it approximate or absolutely precise?

Say you have a base, b.

Then lim q->0 ([b^1+q -b]/q) = b, which through some adjustments gives e = lim n-> infinity (1 +1/n)^n
 
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Yes. In general, when you derive [itex]g^x[/itex], with g any number, the derivative is
[tex]\operatorname{ln}(g) g^x = k \log(g) g^x[/tex], where "ln" is some weird function which turns out to be the logarithm (in base 10), up to a multiplicative constant k.
Now when you plug in some numbers for g, you will find that this function "ln" comes close to unity if you take g to be somewhere around 2.7. Now it would be very cool to know this number g for which g^x is its own derivative exactly, but it turns out not to be anything nice (for example, it is not a fraction, or a square root of something). So we define e to be this number, for which
[tex]\operatorname{ln}(e) = 1[/tex]
and then of course (by the properties of the logarithm) the constant k is
[tex]k = 1/\operatorname{{}^{10}log}(e)[/tex].

So, by (one the many equivalent) definition of e, the derivative of e^x is e^x. As long as you write e and not some numerical approximation like 2.71828... this is an exact identity. Indeed, by definition of the derivative one can show that this requirement of e^x being its own derivative is equivalent to using
[tex]e \stackrel{\text{def}}{\equiv} \lim_{n \to \infty} \left( 1 + \frac{1}{n} \right)^n[/tex].
 
Yes, the number e, like any number, is exact. The derivative of the function ex is exactly ex. Pretty nice function, eh?
 
The coolest function ever defined in calculus is ex. You differentiate or integrate this function you get back the function. Who actually the first to defined such uninteresting function?
 

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