The following show the idea how(adsbygoogle = window.adsbygoogle || []).push({}); a Theveninequivalent source is used to replace the primary circuit of transformer.

https://www.dropbox.com/s/0kaazx1d1srgirz/reflectedsource.jpg?dl=0

https://www.dropbox.com/s/0kaazx1d1srgirz/reflectedsource.jpg?dl=0

In textbook it is commonly stated that the load impedance sees an equivalent source and the open-circuit voltage is given by V_{oc}=NV_{1}=NV_{s}, usually it is said that there is no voltage drop across the source impedance therefore V_{1}=V_{s}in this equation. However, the primary circuit itself is a closed circuit, there should be some current and voltage drop across impedance of the supply, how V_{1}can be equals to V_{s}?

The second question is, the short circuit current is found by NI_{sc}=V_{s}/Z_{s}. It implies that when the secondary circuit is shorted, the primary current will be V_{s}/Z_{s}. It seems that in this case the impedance of the primary coil is ignored. Why?

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# Question about transformer reflected source

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