# Homework Help: Question in homogeneous

1. Feb 17, 2013

### manal950

Hi all

I have question in homogeneous .

You have a serious error right at the start. You have, on the right, $(x+ y)^2$ and you divide that by $x^2$ to get $(1+ y/x)^2= (1+ v)^2$
Up to there you are correct. But then your next line has $1+ v^2$ which is NOT the same thing. $$(1+ v^2)= 1+ 2v+ v^2$$ which works nicely in canceling that "-2v" you will introduce.