Question of Galerkins method of weighted residual- the physical meaning

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Discussion Overview

The discussion revolves around the Galerkin method of weighted residuals, focusing on its physical interpretation and the significance of the weights used in the method. Participants explore the mathematical formulation and implications of the method, particularly in the context of approximating solutions to differential equations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Vishal introduces the Galerkin method and seeks clarification on the physical meaning of the weights in the equation ∫w_i(x)R(x)dx = 0.
  • Some participants explain that the method involves sampling the domain at discrete points and transforming the differential equation into a finite order matrix equation, where the zero represents the error between the approximate and exact solutions.
  • There is a discussion about the residual being the difference between the known right-hand side of the original operator equation and the approximated function, with some participants emphasizing the role of basis functions in this approximation.
  • One participant mentions that the weighted residuals form an NxN matrix, which can be inverted to find the unknown weights on the basis functions, leading to an approximate numerical solution.
  • Vishal requests further clarification on specific equations and examples related to the residual and the formation of the matrix from weighted residuals.

Areas of Agreement / Disagreement

Participants express varying interpretations of the physical significance of the weights and the residuals, indicating that there is no consensus on these aspects. The discussion remains unresolved regarding the specific equations and examples that illustrate these concepts.

Contextual Notes

Participants have not fully defined the assumptions or conditions under which the Galerkin method operates, nor have they resolved the mathematical steps involved in relating the residuals to the matrix formulation.

svishal03
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I have been reading on Galerkins method of weighted residuals according to which an approximate solution to a differential equation is expressed as:

[itex]y^*(x)=Ʃc_iN_i(x)[/itex] where i lies between 1 and n

where y* is the approximate solution expressed as the product of ci unknown,
constant parameters to be determined and Ni (x ) trial functions.

The major requirement placed on the trial functions is that they be admissible functions;
that is, the trial functions are continuous over the domain of interest and satisfy
the specified boundary conditions exactly. In addition, the trial functions should
be selected to satisfy the “physics” of the problem in a general sense.

Given these somewhat lax conditions, it is highly unlikely that the solution represented by
above equation is exact. Instead, on substitution of the assumed solution into the
main differential equation a residual error results.

The method of weighted residuals requires that the unknown parameters ci be evaluated such that:

[itex]∫w_i(x)R(x)dx = 0[/itex]

Can anyone please explain the physical interpretation of the above equation?The physical significance of weights?

What are these weights physically signify?


What is the maigic in these weights such that error (residue) is 0?

Vishal
 
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Please can anyone help?
 
You are sampling the domain of the differential equation at discrete points. You are then writing a linear matrix equation to replace the differential equation. The zero represents the error (difference between the approximate sampled solution and the exact solution.)

The big picture is that you are replacing a general linear operator system (differential equation, integral equation, whatever) with a finite order matrix equation which you then solve numerically to get an approximate answer.
 
Dear Antiphon,

Thank you very much for the reply.

Now,as you said:

You are sampling the domain of the differential equation at discrete points. You are then writing a linear matrix equation to replace the differential equation. The zero represents the error (difference between the approximate sampled solution and the exact solution.)

The big picture is that you are replacing a general linear operator system (differential equation, integral equation, whatever) with a finite order matrix equation which you then solve numerically to get an approximate answer.

Yes- this in effect is the interpretation of:

[itex]y^*(x)=Ʃc_iN_ix[/itex]

I would like to know,that, when we say:

The method of weighted residuals requires that the unknown parameters ci be evaluated such that:

[itex]∫w_i(x)R(x)=0[/itex]

What are we exactly doing ? what is the significance of weight? Can you express an interpretation for this as you did for [itex]y^*(x)=Ʃc_iN_ix[/itex]

Thanks again!

Vishal
 
Ok.

The residual is the difference between the known right-hand side of the original operator equation and the unknown function but approximated by the basis functions and acted upon by the operator. Thats the magic step that turns it from an operator equation into an algebraic one. Because you know the form of the basis functions. There are i=1..N basis functions whose analytic form is given. There are j=1..N weight functions.

The weighted residuals (the definite integral of R and W) evaluated for all i and j form an NxN matrix who's inverse can be multiplied into the coefficients for the known excitation to yield the unknown weights on the basis functions. Once you have the weights, you have the approximate numerical solution to the operator equation.
 
Thanks again..few questions...as below

The residual is the difference between the known right-hand side of the original operator equation and the unknown function but approximated by the basis functions and acted upon by the operator.

Which equation depeicts this statement?- especially when you say;

approximated by the basis functions and acted upon by the operator.

then,

The weighted residuals (the definite integral of R and W) evaluated for all i and j form an NxN matrix who's inverse can be multiplied into the coefficients for the known excitation to yield the unknown weights on the basis functions

Can you give an example for this?
 
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