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Question on calculating the pressure outside lungs of diver

  1. Mar 16, 2012 #1
    Given the following information: a 6.10m long snorkel, density of air = 1.21 kg/m^3, atmospheric pressure = 1.013 x 10^5 P, g = 9.8 m/s^2 and density of seawater = 1.03 x 10^3 kg/m^3, how would you calculate the pressure outside the scuba diver's lungs?

    Would it be anything to do with this equation?

    pressure outside lungs = atmospheric pressure + (density of seawater)*g*(6.10)

    Thanks.
     
  2. jcsd
  3. Mar 16, 2012 #2

    tiny-tim

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    hi jayadds! :smile:

    (i don't see the relevance of the snorkel, especially since i don't think scuba includes a snorkel :confused:)
    that certainly gives the pressure outside his chest :smile:
     
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