Question on calculating the pressure outside lungs of diver

[jayadds]

Given the following information: a 6.10m long snorkel, density of air = 1.21 kg/m^3, atmospheric pressure = 1.013 x 10^5 P, g = 9.8 m/s^2 and density of seawater = 1.03 x 10^3 kg/m^3, how would you calculate the pressure outside the scuba diver's lungs?

Would it be anything to do with this equation?

pressure outside lungs = atmospheric pressure + (density of seawater)*g*(6.10)

Thanks.

 

[tiny-tim]

hi jayadds!

(i don't see the relevance of the snorkel, especially since i don't think scuba includes a snorkel )

pressure outside lungs = atmospheric pressure + (density of seawater)*g*(6.10)

that certainly gives the pressure outside his chest