Question on First Law of Thermodynamics (Paramagnet)

AI Thread Summary
The discussion focuses on the application of the first law of thermodynamics to a paramagnetic substance, specifically the differential form dU = δQ + BdM. There is confusion regarding the relationship between the generalized forces and displacements, particularly how B corresponds to pressure (P) and M to volume (V). A key point is the sign change, leading to the assertion that if B corresponds to P, then M should correspond to -V. It is emphasized that one cannot simply substitute P and V from the ideal gas law to derive the equation of state for a magnetic system, as the relationships will differ. The discussion suggests that Curie's law may be relevant for understanding the behavior of the paramagnetic substance in question.
warhammer
Messages
164
Reaction score
33
Homework Statement
For a pure Paramagnetic substance write down the differential form of first law of thermodynamics and show that C(B)-C(M)=kB^2/T^2

where C(B)=delta (Q)/delta(T) at B constant while C(M)=delta (Q)/delta (T) at M constant.
Relevant Equations
dU= delta (Q) + PdV
For the first part, I have expressed it in the following differential form- dU= delta (Q) + BdM

Now for the second part I am having major confusion. I know that B corresponds to P and M corresponds to V as generalised force and generalised displacement respectively for a Paramagnetic substance.

However I am unsure how to use the differential form as well as the possible equation M=nRT/B (from PV=nRT) in order to obtain the asked relationship. Would be indebted if someone would guide me or highlight my errors above, if any.
 
Physics news on Phys.org
warhammer said:
Relevant Equations:: dU= delta (Q) + PdV
This should be ##dU = \delta Q - PdV##

warhammer said:
For the first part, I have expressed it in the following differential form- dU= delta (Q) + BdM
OK. Note the change in sign where ##+BdM## corresponds to ##-PdV##

warhammer said:
Now for the second part I am having major confusion. I know that B corresponds to P and M corresponds to V as generalised force and generalised displacement respectively for a Paramagnetic substance.
Due to the sign change, if ##B## corresponds to ##P##, shouldn't ##M## correspond to ##-V##?

warhammer said:
However I am unsure how to use the differential form as well as the possible equation M=nRT/B (from PV=nRT) in order to obtain the asked relationship. Would be indebted if someone would guide me or highlight my errors above, if any.
The correspondence ##B \leftrightarrow P## and ##M \leftrightarrow -V## in the first law does not mean that you can obtain the equation of state for the magnetic system by just changing ##P## and ##V## in the equation of state of an ideal gas(!). The equation of state of your system will be an equation that relates ##M, B## and ##T## for your particular substance. You would not expect the equation of state for a paramagnetic substance to be similar in form to the equation of state of an ideal gas. I suspect that you are supposed to assume that your paramagnetic substance obeys Curie's law.
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top