- #1
semc
- 368
- 5
You are designing a rectangular poster to contain 50 cm2 of printing with margins of
4 cm each at the top and bottom and 2 cm at each side. What overall dimensions will
minimize the amount of paper used?
What i did was let the length and breath of the whole poster to be x and y so the area would be 50=(x-4)*(y-8) and perimeter=2(x-4)+2(y-8). Equate the area into the perimeter and differentiate Perimeter wrt y. However i got x=y which means its the maximum area?
Limit as x tends to 0 [tex]\frac{e^x + e^-^x -2}{1-cos2x}[/tex]
Applied Hopital rule once and got 0/2 however answer is 1/2. Am i correct?
4 cm each at the top and bottom and 2 cm at each side. What overall dimensions will
minimize the amount of paper used?
What i did was let the length and breath of the whole poster to be x and y so the area would be 50=(x-4)*(y-8) and perimeter=2(x-4)+2(y-8). Equate the area into the perimeter and differentiate Perimeter wrt y. However i got x=y which means its the maximum area?
Limit as x tends to 0 [tex]\frac{e^x + e^-^x -2}{1-cos2x}[/tex]
Applied Hopital rule once and got 0/2 however answer is 1/2. Am i correct?