Question on rotational transform matrix, I

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SUMMARY

The forum discussion revolves around deriving rotational transform matrices as presented in Tadej Bajd's book on robotics. The user seeks clarification on the similarity of triangles used in the derivation of equations related to the transformation of coordinates. The key equations discussed include x = x' cos(beta) + z' sin(beta) and z = z' cos(beta) - (x' sin(beta)), which are derived from the relationships between segments AB, BC, and CK. The user expresses gratitude after receiving a clear explanation of the concepts involved.

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  • Understanding of basic trigonometry and triangle similarity
  • Familiarity with rotational transformations in robotics
  • Knowledge of coordinate systems and transformations
  • Basic mathematical skills for manipulating equations
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This discussion is beneficial for robotics students, engineers working on robotic systems, and anyone interested in understanding the mathematical foundations of rotational transformations in robotics.

cncnewbee
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Hi,
I'm reading a book called Robotics, written by Tadej Bajd on my own to learn about robotics and have no one else to put my questions other than to the forums.

Here the writer on 11th page writes:

"By considering the similarity of triangles in Figure 2.3, it is not difficult to derive
the following two equations
x..."

where I can't get which triangles to look for similarities as there could be various (I'm no expert in math) and also, can't get how the formula is derived. Please explain

screen shot of book:
i46.tinypic.com/30i9nih.png

Thank you in advance
 
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look at the attachment, I have added new points and lines to your picture to make the proof clear.

We have:x= AB+BC
but BC = x' cos (beta)
and AB = TM sin beta + Mx' sin beta
= (TM+Mx') sin beta
= Tx' sin(beta)
= z' sin (beta) (because Tx' parallel to z')

hence x= x' cos beta + z' sin beta

Similarly,

z = CK -zK
but CK= z' cos(beta)
and zK= z'D= Tz'sin(beta)= x' sin(beta)

hence

z= z'cos beta - (x'sin beta)
 

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  • 30i9nih-new.png
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Quantumjump said:
look at the attachment, I have added new points and lines to your picture to make the proof clear.

Thanks you very much! Now I understand it clearly!
 

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