# Question regarding collisions in 2-dimensions, don't quite understand the process

## Homework Statement

A 1.2kg mass moving 2.4m/s [East] has an elastic collision with a 2.4kg mass moving 1.8m/s [North]. What are the final velocities?

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I know that I need Ek before and after the collision, but I'm not sure how to calculate it for this scenario (a way that would allow me to substitute into Conservation of Momentum find velocities of both objects). I know it's a scaler quantity, so does that mean I do not have to consider making the energy perpendicular to each other?

p = m1v1 + m2v2
Ek = 1/2 mv^2

## The Attempt at a Solution

Here's what I've got so far but I don't know if it's right so I don't want to be doing repeated mistakes throughout my homework and then later on the unit test.

For E-W direction:
p = p'
m1v1 + m2v2 = m1(v1') + m2(v2')
1.2(2.4) + 0 = 1.2(v1') + 2.4(v2')
2.4 = v1' + 2(v2)'

Since it is an elastic collision, I attempted with pure energy since it's scaler, this is what I'm not sure about:
Ek = Ek'
1/2 m(v1)^2 + 1/2 m(v2)^2 = 1/2 m(v1')^2 + 1/2 m(v2')^2
1.2(2.4)^2 + 2.4(1.8)^2 = 1.2(v1')^2 + 2.4(v2')^2
14.688 = 1.2(v1')^2 + 2.4(v2')^2
12.24 = (v1')^2 + 2(v2')^2
12.24 - 2(v2')^2 = (v1')^2
Sqrt {12.24 - 2(v2')^2} = v1'

Then I substituted it into the momentum equation
2.4 = Sqrt {12.24 - 2(v2')^2} +2(v2)'

After squaring both sides and getting the roots of the quadratic equation, I got:
v2' = 2.1 or v2'= -0.51

I reasoned that the ball heading North (v2) should not suddenly start going West when the ball hitting it is heading East.

I end up with final E-W velocities of:
v2' = 2.1m/s [E] and v1' = 1.8m/s [W]
However, these are only Velocities in a East/West direction.

Am I doing this right?
I don't want to do a whole page of calculations for NS direction as well and then make a vector triangle just to find out I did the whole thing wrong.

Thank you for the help!

Last edited:

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I went through with this since I've got no replies :(

Anyways, my results ended up to be:

v1' = 2.3m/s [W38N]
v2' = 2.4m/s [E27N]

These numbers don't seem to make sense at all... The heavier ball starts moving faster after collision and is directed more towards East than what it was initially traveling at in, which was North.

Could someone explain to me what I did wrong? I'm pretty sure my Kinetic Energy equation is iffy.

Redbelly98
Staff Emeritus
Homework Helper
Welcome to PF

Comment #1

The problem does not have a unique solution. We have 4 unknowns (v1x', v1y', v2x', v2y') but only 3 equations (momentum in x-direction, momentum in y-direction, and conservation of energy).

Another piece of information is required to solve the problem. Did the problem statement say anything else?

Comment #2

It seems you are not distinguishing between velocities, and velocity components, properly. For example, in the East-West momentum equation, the final "velocities" are really the x-components of the final velocities, i.e. v1x' and v2x'.

For the kinetic energy treatment, you got the correct initial energy of (1/2)14.688 J. The collision is elastic, as you said, so:

14.688 J = m1(v1x'2+v1y'2) + m2(v2x'2+v2y'2)​

Welcome to PF

Comment #1

The problem does not have a unique solution. We have 4 unknowns (v1x', v1y', v2x', v2y') but only 3 equations (momentum in x-direction, momentum in y-direction, and conservation of energy).

Another piece of information is required to solve the problem. Did the problem statement say anything else?

Comment #2

It seems you are not distinguishing between velocities, and velocity components, properly. For example, in the East-West momentum equation, the final "velocities" are really the x-components of the final velocities, i.e. v1x' and v2x'.

For the kinetic energy treatment, you got the correct initial energy of (1/2)14.688 J. The collision is elastic, as you said, so:

14.688 J = m1(v1x'2+v1y'2) + m2(v2x'2+v2y'2)​