Question regarding finding the magnitude of Torque

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    Magnitude Torque
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SUMMARY

The discussion centers on calculating the magnitude of torque for a system involving two masses attached to a rod, which is rotating at an angle θ degrees from the vertical. The key focus is on defining the vector r, which represents the distance from the pivot point of the rod to the mass. The conversation emphasizes the importance of clear visual aids, as illustrated in the second image shared by the user. The thread was ultimately closed for moderation due to the nature of the question being categorized as schoolwork.

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Harikesh_33
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User has been reminded to post schoolwork-type questions in the Homework Help forums, and to upload images here rather than just linking to them.
TL;DR
https://imgur.com/a/JDUgrrZ

This is the question ,now there are two ways to approach this .

1)Using the formula τ=r×F .
2)Finding L and differentiating it.

Now I approached the problem with the first method .

Since the mass is moving along a circle of radius rsinθ,the centripetal force is F=mrsinθω² ....(1)

https://imgur.com/a/nZogpVO. ...(A)

Here r is the vector from the centre of rod (which is stationery ) to the mass .

Angle between r and F is 90°+θ .

Therefore Torque τ is rFsin(90+
Question regarding finding the magnitude of Torque of a system of two masses attached to a rod rotating at angle of θ degrees with respect to a vertical
 
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What are you considering r to be?

FA00FD8A-D2E0-4177-A22F-1DA48C4F3A08.jpeg

89801AFC-3C1E-4396-89C9-73AB6CAE1462.jpeg
 
The vector from point through which the rod is rotating to the mass .

I have drawn r Vector in second image .
 
Thread closed for Moderation...
 
Thread will remain closed here. @Harikesh_33 -- Please check your PMs. Schoolwork-type questions (even if for self-study) must be posted in the Homework Help forums. Also, please do not just transitory imgur links to the images -- those can disappear which makes your thread make no sense. Please use the "Attach files" link below the Edit window instead. Thank you.
 

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