Question regarding ideal fluids vs. non-ideal fluids

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SUMMARY

This discussion clarifies the behavior of ideal and non-ideal fluids, particularly in the context of blood flow in vessels. In ideal fluids, increasing the cross-sectional area of a pipe decreases the pressure exerted on the walls, while non-ideal fluids, like blood, exhibit different behavior due to factors such as viscosity and shear-thinning properties. The relationship between pipe diameter and pressure drop is governed by Poiseuille's law, which indicates that for a constant mass flux, increasing the diameter reduces the pressure drop. The body regulates blood pressure through vasodilation and vasoconstriction, counteracting increases in pressure by altering vessel diameter.

PREREQUISITES
  • Understanding of fluid dynamics principles, particularly Poiseuille's law.
  • Knowledge of shear-thinning fluids and their properties.
  • Familiarity with concepts of pressure drop and flow rate in pipes.
  • Basic understanding of blood vessel physiology and hemodynamics.
NEXT STEPS
  • Study Poiseuille's law in detail to understand pressure drop calculations.
  • Explore the properties of shear-thinning fluids and their applications in medical contexts.
  • Investigate the physiological mechanisms of vasodilation and vasoconstriction in blood vessels.
  • Learn about the impact of viscosity on fluid flow in various medical scenarios.
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Students and professionals in biomedical engineering, medical practitioners, and anyone interested in fluid dynamics as it relates to human physiology and blood flow mechanics.

Makarov
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I understand that in an ideal fluid, when the cross-sectional area of the pipe is increased, the pressure that the fluid exerts on the walls of the pipe also increases. Also, when the cross-sectional area of the pipe is decreased, the pressure that the fluid exerts on the walls of the pipe decreases.

However, I am a little confused as the how a non-ideal fluid works. Is it the other way around? When the radius of the pipe is decreased, the total peripheral resistance increases, and the pressure on the walls of the pipe rises?

The reason I am asking this question is because I am studying about the blood vessels of the body. Whenever the blood pressure rises, the body causes the vessels to dialate in order to counteract the increase in pressure and keep it constant. This seems to be contrary to what I want to think (increase in radius = increase in pressure). Is my conclusion about non-ideal fluids correct?

Thanks
 
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We assume that the particles within the ideal fluid do not interact and that their volume is negligible. It's not the same in reality, but there is not much deviation (of course, there are some limits). So, many non-ideal fluids act almost the same as the ideal model. So, your conclusion is not quite correct.

You have completely different example with the blood vessels. We cannot ignore the volume of the blood cells and their collisions, so it can't be considered as an ideal fluid. Therefore, some fluid mechanics laws cannot be applied here.

That's my assumption. I'm not sure if it's correct.
 
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I'm not sure what you mean. In Poiseuille flow, there's several parameters- the pressure drop along the pipe, the diameter of the pipe, viscosity of the fluid, etc. I would expect that keeping the volume flow constant, increasing the pipe diameter will decrease the pressure exerted against the wall because the fluid velocity goes down.

Blood is a shear-thinning fluid; the larger the shear rate, the less viscous the fluid. Also, blood pressure can change due to changes in blood volume in addition to vasoconstriction/vasodilation.
 
Consider a flow through a pipe having a diameter D.
For a given mass flux, a bigger passage area means smaller velocity.
Let me call G the mass flux (dm/dt), and V the velocity.
So:

G = \rho V S --> V = G / (\rho S)

The pressure drop due to the friction against the pipe walls is given by:

\Deltap = 1/2 f (L/D) (V^2)/g

Now, let me simplify both equations (because I understand that you're more interested in qualitative explanation) by saying that:

V \propto (G / S)

\Deltap \propto (L/D) V^2

S \propto D^2

Combine these and you obtain that ("\propto" means "proportional to"):

\Deltap \propto L (G^2) / (D^5)

or, for a fixed G:

\Deltap \propto L/(D^5)

So, if you want to decrease the pressure drop and mantain the flow rate of the fluid, you have to either decrease the length of the pipe or to increase it's diameter. That's why our body behaves in a way you have described.

Somewhere in the middle of it there are coefficients and constants like gravity "g", friction factor "f" and some other stuff, but the qualitative explanation is just like that.
 

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