1. The problem statement, all variables and given/known data one gram of ice at 0 degree C contracts in volume by 0.091cc on melting. 9gm of a metalis heated to 200 degree C and dropped into and ice calorimeter. The decrease in volume was found to be 0.0182 cc. Calculate the Sp. heat of the metal (ANS:0.09cal/gmC) 2. Relevant equations 3. The attempt at a solution In my opinion when 80cal/gm is supplied to ice it's volume will decrease by 0.091cc as it will turn into water. So when the Volume decreases by 0.0182 it means that heat supplied will be doubled. so 160 cal/gm = 9gm * S * 200 which which will give s = 0.08cal/gmC.