Question with Archimedes' principles

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To determine how far the cylindrical fishing float will sink into the water, Archimedes' principle states that the upthrust equals the weight of the fluid displaced. The float's average cross-section is 3 cm², and with a lead weight of 30g attached, the volume of water displaced can be calculated using the density of water. The participants agree that the float will sink approximately 0.1 meters based on their calculations. The discussion emphasizes applying Archimedes' principle to find the volume of water displaced and the resulting sinking depth. The calculations confirm the float's behavior in water under the given conditions.
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A cylindrical fishing float is 15cm long, with an average cross section of 3cm^2. It is made of polystyrene and has negligible mass. A lead weight of 30g is attached to the bottom of the float using a thin nylon monofilament line.

Question: Calculate how far the float will sink into the water.

Treat g as equal to 10N kg-1



I know Archimedes said upthrust acting on a body is equal to weight of fluid displaced but can't see how to apply that in this case. Thanks for any help.
 
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Can you find an expression for the volume of the water displaced based on the shape of the float? In this case the density of water can be used to find the mass of the water displaced.
 
DukeLuke said:
Can you find an expression for the volume of the water displaced based on the shape of the float? In this case the density of water can be used to find the mass of the water displaced.

Thanks for your help. I've come up with an answer of 0.1m?
 
You're welcome, I get the same answer.
 

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