Undergrad Questions about my Understanding of Thermodynamics and Statistical Mechanics

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SUMMARY

Heat capacity is a crucial quantity in thermodynamics and statistical mechanics, functioning as an extensible property that changes with the system. It is applicable under constant pressure and volume conditions and is relevant for various molecular types, including monatomic and diatomic molecules. The discussion highlights the distinction between specific heat capacity as an intensive property and its practical application in analyzing thermodynamic changes. Additionally, the relationship between Fermi energy and heat capacity in metals versus gases is explored, emphasizing the unique behavior of delocalized electrons in metals.

PREREQUISITES
  • Understanding of thermodynamic principles, including heat capacity
  • Familiarity with statistical mechanics concepts, particularly the equipartition theorem
  • Knowledge of Fermi energy and its implications in solid-state physics
  • Basic grasp of molecular types (monatomic and diatomic) and their properties
NEXT STEPS
  • Research the practical applications of heat capacity in thermodynamic systems
  • Study the equipartition theorem in the context of electron gases
  • Explore the relationship between Fermi energy and heat capacity in metals
  • Investigate the differences in heat capacity between various molecular types
USEFUL FOR

Students and professionals in physics, particularly those focusing on thermodynamics and statistical mechanics, as well as anyone interested in the behavior of heat capacity in different materials.

Yseult
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Good afternoon all,

I have two questions to check my understanding/understand better those questions.

Why is heat capacity an important quantity in thermodynamics and statistical mechanics?
From my understanding, heat capacity is an extensible property so any change in the system would result in a change in the heat capacity. It also works with constant pressure and volume, making it ideal. Works with different types of molecules (monatomic, diatomic ...).
Is there more to it that I am missing?

The specific heat capacity contribution from the electrons in a metal at RTP differs from the equipartition for electron gas, why?
I understand that electrons have no contribution to heat capacity and only a few are excited by the Pauli exclusions principle. In a metal, electrons are delocalised but in a gas electrons would vibrate more so would have more energy. There is also the idea of the Fermi energy and at lower temperatures, they would have the maximum Fermi energy. But how does the fermi energy relate to the heat capacity?
How would the equipartition be related in this case for electrons? I understand for molecules but not for electrons.

If I could get some help to understand those better that would be great :D
 
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Yseult said:
Good afternoon all,

I have two questions to check my understanding/understand better those questions.

Why is heat capacity an important quantity in thermodynamics and statistical mechanics?
From my understanding, heat capacity is an extensible property so any change in the system would result in a change in the heat capacity. It also works with constant pressure and volume, making it ideal. Works with different types of molecules (monatomic, diatomic ...).
Is there more to it that I am missing?
Specific heat capacity is an intensive property, and changes in other intensive properties will affect specific heat capacity. What you are missing is the "how" of "how is heat capacity applied in practice to analyze thermodynamics changes in physical systems." Without knowing how it can be applied in practice, understanding what it represent is useless.
 
Chestermiller said:
Specific heat capacity is an intensive property, and changes in other intensive properties will affect specific heat capacity. What you are missing is the "how" of "how is heat capacity applied in practice to analyze thermodynamics changes in physical systems." Without knowing how it can be applied in practice, understanding what it represent is useless.
Thank you for the answer! I will look more into it.
 

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