Questions on synthesizing Fluorine 18

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Fluorine-18, used in PET scans, is typically produced by bombarding Oxygen-18 with protons in a cyclotron. An alternative method involves the NEON-20(DEUTERON, ALPHA)FLUORINE-18 reaction, which requires significantly lower energy levels. Neutron bombardment is not a viable method for producing Fluorine-18 due to its neutron-poor nature. Creating a simple deuteron emitter is challenging because deuterons are unstable and have low binding energy, making them unlikely products in nuclear reactions. Ionizing deuterium gas in a particle accelerator is the standard method for generating energetic deuterons.
Strat-O
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I have a couple questions but first some background:

Fluorine 18 is used in PET scans as a beta+ emitter. Generally it is created with an 11-18 MeV cyclotron by bombarding Oxygen 18 with protons. I read a paper that said there was an alternative way to produce F 18 by the NEON-20(DEUTERON, ALPHA)FLUORINE-18 reaction that only requires about 1-3 MeV. My question is, are there other ways that any of you know of to transmute a relatively stable isotope into F 18 by, say neutron bombardment?

Another question:
If you wrap Americium 241 with Beryllium foil you create a neutron source that gives off about 5 MeV neutrons. What's neat about that is it's all passive--nothing to plug in, it just works. Is there a way that you can create a Deuteron emitter that works just as simply?

Thanks!

Marlin
 
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Natural, stable F is 19F. 18F has one less neutron for that number of protons, which is why it decays by positron emission. Because it's on the neutron-poor side of the line of optimal stability, you really can't produce it by irradiating a target material with neutrons.

A deuteron is quite an unstable nucleus - it has relatively low binding energy per nucleon, which is why it likes to react with other light nuclei in reactions such as D-D and D-T fusion, for example.

Because it's relatively weakly bound, it's very unlikely to be found as the product of a nuclear reaction, analogous to the 9Be(alpha, n)12C reaction that goes on inside an alpha-Be neutron source.

To make a source of energetic deuterons, you ionise deuterium gas within the ion source of a particle accelerator such as a cyclotron, just as you would with unenriched hydrogen if you were using a proton beam.
 
Thank you Minerva. Looks like good info.

Marlin
 
Hello, I'm currently trying to compare theoretical results with an MCNP simulation. I'm using two discrete sets of data, intensity (probability) and linear attenuation coefficient, both functions of energy, to produce an attenuated energy spectrum after x-rays have passed through a thin layer of lead. I've been running through the calculations and I'm getting a higher average attenuated energy (~74 keV) than initial average energy (~33 keV). My guess is I'm doing something wrong somewhere...

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