Quick calculation of lattice parameter and unit cell volume for germanium?

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To calculate the dhkl for the (111) direction of germanium, use the formula dhkl = a/sqrt(3), where 'a' is the lattice parameter of 5.658 angstroms. The unit cell volume (vc) can be determined by cubing the lattice parameter, as it represents the side length of a cubic unit cell. The discussion clarifies that 'a' specifically refers to the lattice parameter, not the atomic radius. For a cubic system, assuming no other dimensions are provided, this approach is valid. Understanding these calculations is essential for accurately determining the properties of germanium.
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Homework Statement


Calculate dhkl and vc for the (111) direction of germanium.



Homework Equations


dhkl=a/sqrt(h2+k2+l2)

vc=unit cell volume=a1dot(a2xa3)

or

vc=structure form factor/density


The Attempt at a Solution


dhkl=a/sqrt(3)

I know how to solve this, I've just forgotten whether a refers to the lattice parameter (5.658 angstroms) or the atomic radius (1.52 angstroms).

for calculating the unit cell volume, I'm a little bit more lost. Could I just take the lattice parameter and cube it, since it's the side length of the unit cell? Thanks in advance.
 
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