Quick question about transformer circuit

Click For Summary

Homework Help Overview

The discussion revolves around a transformer circuit problem, focusing on the calculation of currents and voltages within the circuit. Participants are analyzing their approaches to solving the problem and verifying their results.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various equations related to the transformer circuit, including relationships between primary and secondary currents and voltages. There are attempts to verify calculations and clarify the reasoning behind certain values, such as the resistance sum equated to 20mΩ.

Discussion Status

Some participants are sharing their calculations and seeking validation of their results. Others are encouraging self-checking of answers and suggesting that explaining the thought process could enhance understanding. Multiple interpretations of the problem are being explored, with no explicit consensus reached.

Contextual Notes

There are indications of potential errors in initial calculations, and participants are reflecting on their approaches. The discussion includes references to specific values and relationships in the circuit, but no definitive conclusions are drawn.

loki4000
Messages
15
Reaction score
0

Homework Statement



Can someone inform me wheher my solution is correct?
2i89cmd.jpg


Homework Equations


V1 = E2 * (10^-3)/2*(10^-3) = 0.001
V2 = E1
Ra = (R2+R3) = 0.02
Rb = R1 = 30
n = (1/100)
n^2 = (1/100)^2

The Attempt at a Solution


I1 = (V'1 - V2)/(Ra'+Rb)
I1 = (0.001/n - 230)/(0.02/n^2 + 30)
I1=-0.9995652174
 
Physics news on Phys.org
loki4000 said:
Ra = (R2+R3) = 0.02
Why is this sum equated to 20mΩ ?
 
NascentOxygen said:
Why is this sum equated to 20mΩ ?
Yup, my error.
Anyway, after looking at problem again I solved it in different way. I think this way makes more sense (at least to me).
Previous solution did not count ).
So, can you tell me whether this one correct?

I2 = current over R2
a=100/1=100
I2=aI1
V2=V1/a
V2 = (-I1R1+E)/a
V2 = (-I2R2)+(E2* (R2/(R1+R2)))
(-I2R2)+(E2* (R2/(R1+R2)))=(-I1R1+E)/a

-(10^-3)I2+(0.6667)=-(3/10)I1+2.30

-0.1I1+(0.6667)=-(3/100)I1+2.30
-0.1I1+(3/10)I1=+2.30-(0.6667)
0.2I1 = 1.6333
I1 = 8.1665
 
loki4000, you really don't need anyone else to check your answer---because you can do the check yourself. Substitute your answer and see what the figures look like.

For example, you determined the primary current to be a little over 8A? What voltage loss would that give you across the primary's resistance, and does that sound reasonable?
 
I think you should first explain in words how you will go about solving this. It would help you, and it will be easier for others to follow what you are doing.
 
Never mind. I solved it. Thanx for reply anyway.
 
loki4000 said:
Never mind. I solved it. Thanx for reply anyway.
What answer did you get for the primary current?
 
I1=0.5 A
 
loki4000 said:
I1=0.5 A
That is my answer, too. :cool:
 

Similar threads

Replies
22
Views
4K
Replies
10
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
16
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K