Quick question about transformer circuit

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SUMMARY

The discussion revolves around solving a transformer circuit problem involving primary and secondary currents, voltage equations, and resistance values. The user initially calculated the primary current (I1) using the formula I1 = (V'1 - V2)/(Ra + Rb) and later revised their approach to find I2, the current over R2, using the turns ratio (a = 100). The final value for I1 was confirmed to be 0.5 A, aligning with another user's calculation, indicating the solution's correctness.

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loki4000
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Homework Statement



Can someone inform me wheher my solution is correct?
2i89cmd.jpg


Homework Equations


V1 = E2 * (10^-3)/2*(10^-3) = 0.001
V2 = E1
Ra = (R2+R3) = 0.02
Rb = R1 = 30
n = (1/100)
n^2 = (1/100)^2

The Attempt at a Solution


I1 = (V'1 - V2)/(Ra'+Rb)
I1 = (0.001/n - 230)/(0.02/n^2 + 30)
I1=-0.9995652174
 
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loki4000 said:
Ra = (R2+R3) = 0.02
Why is this sum equated to 20mΩ ?
 
NascentOxygen said:
Why is this sum equated to 20mΩ ?
Yup, my error.
Anyway, after looking at problem again I solved it in different way. I think this way makes more sense (at least to me).
Previous solution did not count ).
So, can you tell me whether this one correct?

I2 = current over R2
a=100/1=100
I2=aI1
V2=V1/a
V2 = (-I1R1+E)/a
V2 = (-I2R2)+(E2* (R2/(R1+R2)))
(-I2R2)+(E2* (R2/(R1+R2)))=(-I1R1+E)/a

-(10^-3)I2+(0.6667)=-(3/10)I1+2.30

-0.1I1+(0.6667)=-(3/100)I1+2.30
-0.1I1+(3/10)I1=+2.30-(0.6667)
0.2I1 = 1.6333
I1 = 8.1665
 
loki4000, you really don't need anyone else to check your answer---because you can do the check yourself. Substitute your answer and see what the figures look like.

For example, you determined the primary current to be a little over 8A? What voltage loss would that give you across the primary's resistance, and does that sound reasonable?
 
I think you should first explain in words how you will go about solving this. It would help you, and it will be easier for others to follow what you are doing.
 
Never mind. I solved it. Thanx for reply anyway.
 
loki4000 said:
Never mind. I solved it. Thanx for reply anyway.
What answer did you get for the primary current?
 
I1=0.5 A
 
loki4000 said:
I1=0.5 A
That is my answer, too. :cool:
 

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