How Does Acceleration Affect Speed Skater's Velocity on Rough Ice?

[slcaha2]

1. A speed skater moving across frictionless ice at 8.20 hits a 4.60-m-wide patch of rough ice. She slows steadily, then continues on at 5.30 .
SLC: I am assuming that Vf = 5.3 m/s ; Vi = 8.2 m/s ; d = 4.60 m ; a =? ; t = ?.
Can you get me started with a correct forumula? I am fairly certain I can get the answer from there.

Thanks!

 

[thermodynamicaldude]

Vf^2 = Vi^2 + 2a(d)

d = Vi (t) + .5at^2

These are two of the general equations for kinematics.

 

[M98Ranger]

Sure, the correct formula to use in this scenario would be the equation of motion: Vf^2 = Vi^2 + 2ad, where Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and d is the distance traveled. From there, you can rearrange the equation to solve for either a or t, depending on which variable you are looking for. I hope this helps get you started!