Quick Uncertainty in an Average Question

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SUMMARY

The discussion centers on calculating the uncertainty of an average when two identical measurements with equal uncertainties are involved. The key conclusion is that the variance of the average is derived from the average of the variances divided by the number of measurements. In this specific case, since both measurements have the same variance, the variance of the average is half of that common variance. Consequently, the uncertainty of the average is the original uncertainty divided by the square root of 2.

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I took two measurements of angles that have the same uncertainty. These two angles are also equal. So I took an average of these angles and it's the same result originally measured, but when I try finding the UNCERTAINTY OF THE AVERAGE, I get 0. I'm guessing this isn't the right thing to put in my lab report.

So how does it work when you have two exact same measurements with equal errors, how do you get the uncertainty of the average?

Thanks
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In general the variance of the average is the average of the variances divided by the number of terms. In your case, since the variances are the same, the variance of the average is half the common variance. The uncertainty (square root of variance) is therefore the original uncertainty divided by the square root of 2.
 

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