Quickly Add Vector Components: Expert Tips for Solving Vector Problems

Thread starter physicssux
Start date Feb 17, 2006
Tags

Components Vector Vector components

AI Thread Summary

To add three different vector components, sum the individual components for each vector. For vectors expressed as a = xi + yj + zk and b with different values, the resultant vector is obtained by adding the corresponding components. For example, if a = i + j and b = 2i + j, the sum results in a + b = 3i + 2j. This method applies consistently regardless of the number of vectors involved. Understanding this component-wise addition simplifies solving vector problems effectively.

Feb 17, 2006

physicssux

how do i add up 3 different vector components...

i tried drawing them up in scale but had NO LUCK...some one please help.

Physics news on Phys.org

Feb 17, 2006

finchie_88

If you have two vectors, let's say a = xi + yj + zk, and b (same thing, but different values of x,y and z, then, the sum of them is simple the sum of the components. The same holds true for 3 vectors.
eg. a = i+j, b = 2i +j, then a+b = 3i + 2j

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »