# Electrons are moving in a uniform magnetic field of 50 Oersted having a velocity of 8.8 x 10^6 cm/sec. What is the radius of the circular path they follow?(adsbygoogle = window.adsbygoogle || []).push({});

I solved it in the following way:

In C.G.S system 1 Gauss = 1 Oersted (In vacuum)

So, B = 50 Gauss

V = 8.8 x 10^6 cm/sec

Let e be the charge of the electron, r be radius of its circular path and m be its mass.

e = 1.6 x 10^(-19) Coulomb = 4.8 x 10^(-10) Stat Coulomb

m = 9.1 x 10^(-28) grams

In a perpendicular magnetic field,

BeV = {m(V^2)}/r

r = (mV)/(Be)

Solving I get,

r = 3.3 x 10^(-13) cm

I think somewhere I have gone wrong as the radius is too small. Please help.

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# Homework Help: Radius of path of electron in a magnetic field

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