Radius of proton motion in Magnetic field

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SUMMARY

The discussion focuses on calculating the radii of proton motion in the van Allen belts under a magnetic field strength of 0.1 G. The user calculated the radii for protons with energies of 0.1 MeV, 1 MeV, and 10 MeV, yielding values of 3.847 km, 12.13 km, and 38.5 km, respectively. However, these results differ from the expected values of 4.6 km, 14.0 km, and 46.0 km provided by Mastering Physics. Key equations used include kinetic energy (K = 1/2 mv²) and the Lorentz force equation (r = mv/qB), with the mass of the proton as 1.67 x 10-27 kg and charge as 1.9 x 10-19 C.

PREREQUISITES
  • Understanding of kinetic energy equations (K = 1/2 mv²)
  • Familiarity with the Lorentz force equation (F = q(v x B))
  • Knowledge of magnetic field strength conversion (G to T)
  • Basic understanding of proton properties (mass and charge)
NEXT STEPS
  • Research the conversion of magnetic field strength from Gauss to Tesla.
  • Study the effects of altitude on particle motion in magnetic fields.
  • Learn about the dynamics of charged particles in magnetic fields, particularly in astrophysical contexts.
  • Explore the implications of energy conversion from MeV to Joules in particle physics.
USEFUL FOR

Students in space weather physics, physicists studying particle dynamics, and anyone interested in the behavior of charged particles in magnetic fields.

gills
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Homework Statement


ou're taking a class in space weather physics. Space weather deals with the dynamics of the far upper atmosphere and the magnetic regions surrounding the Earth. You're preparing a term paper on the van Allen belts, regions where high-energy particles are trapped in the Earth's magnetic field. Your textbook says the magnetic field strength at the belts is 0.1 G. To impress your professor, you calculate the radii of the spiral paths of 0.1-MeV, 1-MeV, and 10-MeV protons in the van Allen belts.

What values do you get for r(0.1 MeV), r(1 MeV), and r(10 MeV) in km?

Homework Equations


K = \frac{1}{2}mv^{2}

F_{B} = m\vec{a} = m\frac{v^{2}}{r} = q\vec{v} x \vec{B}


The Attempt at a Solution



I keep getting the same values, but the mastering physics answers are different.

First I convert the MeV values into Joules which =

0.1 MeV = 100,000eV = 1.6*10^{-14} J
1MeV = 1.6*10^{-13} J
10MeV = 1.6*10^{-12} J

then knowing the energy each proton has, we can find the velocities from:
K = \frac{1}{2}mv^{2}
v=\sqrt{\frac{2K}{m}}

then knowing the velocities, we solve for the radius using Lorentz eq.:

r = \frac{mv}{qB}

and from this I'm getting:

r(0.1 MeV) = 3.847 km
r(1 MeV) = 12.13 km
r(10 MeV) = 38.5 km

The mastering physics answers are:
4.6 km
14.0 km
46.0 km respectively


Is there something that I'm forgetting in my eq's? Should I be considering gravitational potential energy because the particle is at an altitude above the surface of the earth?

i actually tried this with some basic research on the altitude of the Van Allen belt where protons are, but the range I found was very large, and the velocities ended up being almost identical.

Any thoughts would be much appreciated.
 
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Are you sure you're using the right mass for a proton, or converting G into T? My answer for the first one matches the Mastering Physics answer.
 
Snazzy said:
Are you sure you're using the right mass for a proton, or converting G into T? My answer for the first one matches the Mastering Physics answer.

I have a feeling I'm making a stupid mistake.

Mass proton = 1.67 * 10^{-27} kg

0.1G = 0.00001 T = 1 * 10^{-5} T

is that what you're using?
 
Snazzy said:
Are you sure you're using the right mass for a proton, or converting G into T? My answer for the first one matches the Mastering Physics answer.

I have a feeling I'm making a stupid mistake.

Mass proton = 1.67 * 10^{-27}

0.1G = 0.00001 T = 1 * 10^{-5} T

q = 1.9 * 10^{-19} C

is that what you're using?
 
gills said:
q = 1.9 * 10^{-19} C

:rolleyes:
 
YUP! the same crap i do on my exams!
 

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