Raising a bunch of matrices to a power

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SUMMARY

The discussion focuses on the simplification and computation of the expression (ABC)^5 for nxn matrices A, B, and C. It is established that if A, B, and C commute (i.e., AB = BA, AC = CA, and BC = CB), then the expression can be simplified to (A^5)(B^5)(C^5). For the fastest computation method, participants suggest multiplying ABC directly and then diagonalizing the result, although they also explore using commutators to express the product, which can lead to complex and less practical forms.

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sjeddie
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Let A, B, and C be nxn matrices,
I'm wondering
1. is it possible to simplify (ABC)^5 to expand it ( maybe into something like (A^5)(B^5)(C^5) )
2. what's the fastest way of solving (ABC)^5? I'm thinking actually multiply ABC out, then diagonalize it. Is there a faster way?
 
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sjeddie said:
Let A, B, and C be nxn matrices,
I'm wondering
1. is it possible to simplify (ABC)^5 to expand it ( maybe into something like (A^5)(B^5)(C^5) )
Under certain conditions. If A, B and C commute among themselves (that is, AB = BA, AC = CA and BC = CB) then this is possible.

sjeddie said:
2. what's the fastest way of solving (ABC)^5? I'm thinking actually multiply ABC out, then diagonalize it. Is there a faster way?

I'm thinking the same thing. Alternatively you could try writing down an expression in terms of A^5, B^5, C^5 and the commutators [A, B] = AB - BA, [A, C] = AC - CA and [B, C] = BC - CB, e.g.
(A B C)^2 = A B C A B C
... = A B A C B C + A B [C, A] B C
... = A^2 B C B C + A [B, A] C B C + A B [C, A] B C
... = A^2 B^2 C^2 - A^2 B [B, C] C - A [A, B] C B C - A B [A, C] B C

But that is in general ugly and not very helpful.
 
Thank you CompuChip
 

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