Real variables x and y are related by the equation
3ln(y +4) = 2ln(x +2) − 2ln(x +9)+3ln(x^2 − 1).
Determine the range of values of x and y for which the expressions on each side of this equation are defined.
Find y explicitly as a function of x, that is, express the equation in the form y = f(x), simplifying your answer as far as possible.
Show that the expressions √3cos(5t + π/6) and (√3/2)(√3cos(5t) − sin(5t)) are equivalent.
The Attempt at a Solution
I assume y must be > -4 to make the ln of a real number. As for x I have no idea which one to use, do I have to expand them somehow? Or is it simply x^2 > 1 and x > -9 and x > -2 leaving us with the lowest x > -9
Uhm.... no idea really, please give me a clue. Something tells me its substituting identities and simplification.