Raoult's Law, Finding an unknown compound

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The discussion centers on determining the identity of compound X based on its boiling point elevation in a 1.00m aqueous solution. The boiling point elevation constant for water is provided as 0.52, leading to a calculated change in boiling point of 1.04 degrees Celsius. This change suggests that two particles are present in the solution, as indicated by the calculation of 1.04/0.52 = 2. The participant hypothesizes that KCl (potassium chloride) is the likely candidate for compound X due to its dissociation into two ions. The discussion concludes with a request for confirmation of this reasoning.
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1. A 1.00m aqueos solution of compound X had a boiling point of 101.04 Celsius. Which one of the following could be compound X? The boiling point elevation constant for water is 0.52

A) CH3CH2OH
B) KCL
C) C6H12O6
D) NA3PO4




ΔTb=(Kb)(m)




1: identify the change in bp temperature. in this case, it's 101.04-100 = 1.04 degrees C.
2. divide this change by your bp elevation constant. 1.04/0.52 = 2

so now I think that means that two different molecules were added. My guess is it was KCl (potassium chloride). but of course, I'm not entirely sure =/

Can someone help me out?

 
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Looks OK to me.
 
Thanks Borek!
 
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