1. The problem statement, all variables and given/known data A balloon is being tracked from an observation point 0.42 mi from its launch site. Both the launch site and observation point are on level ground. How fast is the angle of elevation to the top of the balloon increasing at the instant it is 20°, if the balloon is rising vertically at a rate of 35 ft/sec. Express the solution in degrees/sec. 2. Relevant equations 3. The attempt at a solution .42 mi=2217.6 ft tanθ=h/b Differentiated: sec^2(20°) dθ/dt=1/.2217.6 ft dh/dt sec^2(20°) dθ/dt=1/2217.6 ft (35) dθ/dt=0.008999 I know the answer is supposed to be .799°/sec but I just can't see where my mistake is. Any help would be appreciated.